3rd Cycle Assessment#1 Mathematics 9
Quiz by Jaylord Arguelles
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- Q1
An equation containing a single variable of degree 2
Quadratic Equation
Cubic Equation
Quartic Equation
Linear Equation
30sEditDelete - Q2
The other term for the obtained values of the variable in a given equation
Users re-arrange answers into correct orderJumble30sEditDelete - Q3
Solve using square roots:x2 = 36
36 or 6
6
6 or -6
6 or -6
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Solve using square roots:x2 - 64 = 0
64
8
8 or -8
1 or -64
30sEditDelete - Q5
Solve using square roots:(x - 2)2 = 16
4 or -4
6 or -2
-6 or 2
6
30sEditDelete - Q6
Solve by factoring: (Hint: set equation to 0) x2 + 6x = 27
27 or -3
9 or -3
6 or -6
3 or -9
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Solve by factoring: (Hint: set equation to 0)x2 + 10x = 75
5 or -15
10 or 75
15 or -5
10 or -10
30sEditDelete - Q8
Solve using the quadratic formula:
x2 + 4x + 4 = 0
-2
2
2 and 0
-2 and 0
30sEditDelete - Q9
Solve using the quadratic formula:2x2 + 5x - 3 = 0
-6 and 1
3 and 0.5
2 and -3
0.5 and -3
30sEditDelete - Q10
What are the solutions to this equation?(x-3)(x+2)=0
x=3,-2
x=-3,2
x=3,2
x=2,3
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Does the parabola open up or down? y = -3x2 +7x - 2
up
down
30sEditDelete - Q12
Complete the Square
x2 + 6x + 20
(x + 3)2 + 29
(x + 3x)2 + 11
(x + 3)2 + 11
(x + 6)2 + 11
30sEditDelete - Q13
When factoringx2 - 4x + 4 = 20,what goes in the blank?(x - __ )2 = 20
8
2
20
4
30sEditDelete - Q14
Rewrite this quadratic in factored form: x2- 15 = 1
(x + 4) (x + 4)
(x - 4)(x - 4)
(x - 8)(x + 2)
(x - 4)(x + 4)
30sEditDelete - Q15
What is the discriminant?
b2/2a
4ac
b2±4ac
b²-4ac
30sEditDelete - Q16
If the discriminant equals 0, then the quadratic has:
No Real Solution
2 Real Solutions
Half a Solution
1 Real Solution
30sEditDelete - Q17
If the discriminant is positive, then the quadratic has:
Half a Solution
1 Real Solution
No Real Solution
2 Real Solutions
30sEditDelete - Q18
b2 - 4ac would equal: y = 2x2 -x -3
-25
25
-23
0
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- Q2030sEditDelete