Question 1

An error ______ for a number

x

shows the range of possible values of

x

.

Accepted Answer

interval

Question 2

Using estimation only which of the following is the correct answer to

{{214^2	imes2.875}\over37.06}

Accepted Answer

3552.711819

Answer

355271.1819

Answer

355.2711819

Answer

3552711.819

Answer

35527.11819

Question 3

Estimate the value of

{{214^2	imes2.875}\over37.06}

Accepted Answer

400

Question 4

Which of the following calculations will give the lower bound of

{{214^2	imes2.875}\over37.06}

?

Accepted Answer

a^2=LB_{c^2}-UB_{b^2}

Answer

a^2=LB_{c^2}-UB_{b^2}

Answer

a^2=LB_{c^2}-UB_{b^2}

Answer

a^2=LB_{c^2}-UB_{b^2}

Question 5

If

{{214^2	imes2.875}\over37.06}

and

x

. Find the value of

x

and the appropriate degree of accuracy in significant figures.

Accepted Answer

a^2=LB_{c^2}-UB_{b^2}

= 0.46 (2 s.f.)

Answer

a^2=LB_{c^2}-UB_{b^2}

= 0.45 (3 s.f.)

Answer

a^2=LB_{c^2}-UB_{b^2}

= 0.45 (2 s.f.)

Answer

a^2=LB_{c^2}-UB_{b^2}

= 0.456 (3 s.f.)

Answer

a^2=LB_{c^2}-UB_{b^2}

= 0.46 (3 s.f.)

Question 6

a^2=LB_{c^2}-UB_{b^2}

= 2.64 (3 s.f.),

b

= 1.655 (4 s.f.),

c={\sqrt{a}\over{b^3}}

. Work out the value of

c

to a suitable degree of accuracy.

Accepted Answer

a^2=LB_{c^2}-UB_{b^2}

= 0.36 (2 s.f.)

Answer

a^2=LB_{c^2}-UB_{b^2}

= 0.35 (2 s.f.)

Answer

a^2=LB_{c^2}-UB_{b^2}

= 0.358 (3 s.f.)

Answer

a^2=LB_{c^2}-UB_{b^2}

= 0.35 (3 s.f.)

Answer

a^2=LB_{c^2}-UB_{b^2}

= 0.36 (3 s.f.)

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