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Cluster 5 NC.8.EE.8 Review

Quiz by D Stafford

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14 questions
Show answers
  • Q1

    Two numbers have a difference of 17 and a sum of 23. Which system equations can be used to determine x and y, the two numbers?

    x - y = 17 and x - y = 23

    x + y = 17 and x - y = 23

    x + y = 17 and x + y = 23

    x - y = 17 and x + y = 23

    300s
  • Q2

    A system of two linear equations has no solution. When the lines are graphed on the same coordinate plane, they are

    perpendicular

    parallel

    intersecting

    equivalent

    60s
  • Q3

    Susan bought some potted plants. Petunias cost $7 per pot and begonias cost $8 per pot. She purchased 22 potted plants and spent a total of $163. How many petunias did Susan buy?  

    9

    11

    7

    13

    300s
  • Q4

    How many intersection points do the graphs of these two equations have? 

    2x + 3y = 7 and 4x + 6y = 14

    2

    0

    1

    infinite

    120s
  • Q5
    120s
  • Q6
    Which of the following systems of equations has no solution?
    3x + 4y = 12 and 6x - 8y = -12
    x + y = 5 and x - y = 1
    y = -x + 1 and 2x + y = 4
    y = 2x + 3 and 4x - 2y = 8
    120s
  • Q7
    120s
  • Q8
    Which pair of lines will intersect at a single point?
    y = 3x + 1 and y = -2x + 4
    y = 5x + 7 and y = 5x + 9
    y = -x + 6 and y = -x + 2
    y = 4x + 2 and y = 4x - 3
    120s
  • Q9
    120s
  • Q10
    120s
  • Q11
    120s
  • Q12

    What point represents the solution to the following system of equations?

    y = 3x - 6 and x + 3y = 12

    (1, -3)

    (-3, 5)

    (4, 6)

    (3, 3)

    120s
  • Q13

    What is the y value of the following system of equations? 

    y = 2x - 6 and y = 5x - 21

    5

    4

    12

    9

    120s
  • Q14

    The members of a drama club sold tickets to a school play. Each student ticket costs $5, and each adult ticket costs $7. They sold 28 more student tickets than adult tickets. The total ticket sales were $800. Which equation can be used to determine the number of adult tickets sold?

    5(s + 28) + 7s = $800

    5(a + 28) + 7s = $800

    5(a + 28) + 7a = $800

    5(s + 28) + 7a = $800

    300s

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