D and F block elements
Quiz by RAJI ABISH
Feel free to use or edit a copy
includes Teacher and Student dashboards
Measure skillsfrom any curriculum
Tag the questions with any skills you have. Your dashboard will track each student's mastery of each skill.
- edit the questions
- save a copy for later
- start a class game
- automatically assign follow-up activities based on students’ scores
- assign as homework
- share a link with colleagues
- print as a bubble sheet
- Q1
CuSO4 is paramagnetic while ZnSO4 is diamagnetic because
Cu2+ ion has 3d9 configuration while Zn2+ion has 3d10 configuration
Cu2+ has half filled orbitals while Zn2+ hasfully filled orbitals
CuSO4 is blue in colour while ZnSO4 iswhite.
Cu2+ ion has 3d5 configuration while Zn2+ion has 3d6 configuration
30s - Q2
The magnetic moment of a divalent ion inaqueous solution with atomic number 25 is
9.9 B.M
6.9 B.M
5.9 B.M
2.9 B.M
45s - Q3
Highest oxidation state of manganese influoride is +4 (MnF4) but highest oxidation statein oxides is +7 (Mn2O7) because
fluorine does not possess d-orbitals
fluorine stabilises lower oxidation state
in covalent compounds, fluorine can form single bond only while oxygen forms double bond.
fluorine is more electronegative than oxygen
45s - Q4
Which of the following transition metal ions is colourless?
Cr3+
Zn2+
Cu+2
V2+
20s - Q5
Which of the following d-block element has half-filled penultimate as well as valence subshell?
Cu
Ag
Cr
Au
20s - Q6
E°Mn3+/Mn2+ is highly positive than that of E°Cr3+/Cr2+ or E°Fe3+/Fe2+ because
Mn3+ is more stable than Mn2+ due to higher oxidation state.
second ionisation enthalpy of Mn is higher than third ionisation enthalpy.
third ionisation enthalpy of Mn is much larger due to stable half filled d5 electronic configuration of Mn2+
Mn2+ (d5) can be easily oxidised to Mn3+(d4)due to low ionisation enthalpy
45s - Q7
Interstitial compounds are nonstoichiometric compounds formed by trapping small atoms like C, H or N in crystal lattices of transition metals. Which of the following properties is not shown by these compounds?
They are chemically very reactive.
They are very hard, some borides arecomparable to diamond in hardness.
They retain metallic conductivity.
They have high melting points, higher than those of pure metals
45s - Q8
Cu+ ion is not stable in aqueous solution because
hydration energy of Cu+(aq) is much more negative than that of Cu2+(aq)
large value of second ionisation enthalpy of copper is compensated by much more negative hydration energy of Cu2+(aq)
many copper (I) compounds are unstable in aqueous solution and undergo disproportionation reaction.
second ionisation enthalpy of copper is less than the first ionisation enthalpy
45s - Q9
Following order is observed in oxidizing power of certain ions:VO2+ < Cr2O72– < MnO4 -
increasing stability of the lower species to which they are reduced
increasing stability of the higher species to which they are oxidised
increasing stability of the higher species to which they are reduced
increasing stability of the lower species to which they are oxidised.
45s - Q10
Transition metals make the most efficient catalysts because of their ability to
adopt multiple oxidation states and to form complexes
form coloured ions
form a large number of oxides.
show paramagnetism due to unpaired electrons
45s - Q11
Although zirconium belongs to 4d and hafnium to 5d-transition series even they show similar physical and chemical properties because both
have same number of electrons
belong to d-block
have similar atomic radius
belongs to the same group of the periodic table.
20s - Q12
The second and third row elements of transition metals resemble each other much more than they resemble the first row because of
diagonal relationship between second and third row elements
lanthanoid contraction which results in almost same radii of second and third row metals
similar oxidation states of second and third row metals.
similar ionisation enthalpy of second and third row elements
45s - Q13
Correct statement about W, X, Y and Z is
W3+ ion is green in colour
magnetic moment of X in its +2 oxidation state is 2.83 B.M.
stable oxidation states of Z are +1, +2 and+6.
Y3+ catalyses reaction between iodide and persulphate ions.
45s - Q14
Few electrode potential values are given below: On the basis of these values, Krish concluded the following statements:
I. Cr2+ is a reducing agent
II. Mn3+ is an oxidizing agent
III. both Cr2+ and Mn3+ exhibit d4 electronic configuration
IV. when Cr2+ is used as a reducing agent, the chromium ion attains d5 electronic configuration.
The incorrect conclusion made by him is
III
IV
II
I
60s - Q15
Use the data to answer the following and also justify giving reasons :
(i) Which is a stronger reducing agent in aqueous medium, Cr2+ or Fe2+ and why?
(ii) Which is the most stable ion in +2 oxidation state and why?
Users enter free textType an Answer60s
