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GEN MATH Q2 Formative Assessment #1: Representing Real-Life Situations Using Rational Functions

QuizΒ by JONALD ROSARIO

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10 questions
Show answers
  • Q1
    120s
  • Q2
    120s
  • Q3
    120s
  • Q4
    120s
  • Q5
    120s
  • Q6

    A printing shop charges a fixed setup fee of β‚±1,200 for any printing job, plus β‚±2 per page printed. Which rational function represents the cost per page for printing π‘₯ pages?

    C\left(x\right)=\frac{2x}{1200+x}

    C\left(x\right)=\frac{2}{x}+1200

    C\left(x\right)=\frac{1200+2x}{x}

    C\left(x\right)\ =\ 1200x+2

    120s
  • Q7

    A gym charges a β‚±1,500 registration fee and β‚±400 per month for membership. What rational function represents the average monthly cost if a person is a member for π‘₯ months?

    C\left(x\right)=\frac{1500+400}{x}

    C\left(x\right)=1500+400x

    C\left(x\right)=\frac{400x+1500}{x}

    C\left(x\right)=\frac{400x+1500}{x}

    120s
  • Q8

    A moving company charges β‚±8,000 for the first 3 hours and β‚±500 for every additional hour. If π‘₯ is the total number of hours, what rational function represents the average cost per hour of using the service?

    C\left(x\right)=8000+500\left(x-3\right)

    C\left(x\right)=\frac{500x+8000}{x}

    C\left(x\right)=\frac{8000+500\left(x-3\right)}{x}

    C\left(x\right)=\frac{500x}{8000+x}

    120s
  • Q9

    A phone company offers a plan that charges β‚±1,500 for the first 100 minutes, and β‚±2 per minute for any additional minutes. Which rational function represents the average cost per minute if a customer uses the phone for π‘₯ minutes?

    C\left(x\right)=\frac{1500+2\left(x-100\right)}{x}

    C\left(x\right)=\frac{1500+2x}{100}

    C\left(x\right)=\frac{1500x+2\left(x-100\right)}{x}

    C\left(x\right)=1500x+2x

    120s
  • Q10

    A software subscription service has a sign-up fee of β‚±1,000 and charges β‚±200 per month. What rational function represents the average cost per month if a customer subscribes for π‘₯ months?

    C\left(x\right)=\frac{200+1000}{x}

    C\left(x\right)=200x+1000

    C\left(x\right)=\frac{1000x}{200}

    C\left(x\right)=\frac{1000+200x}{x}

    120s

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