Question 1

Find the inverse of the function.  $f(x)=(x+3)^2 +4$

Accepted Answer

$f^{-1}(x)=-3\pm\sqrt{x-4}$

Answer

$f^{-1}(x)=-3\sqrt{x-4}$

Answer

$f^{-1}(x)=\pm\sqrt{x-3}-4$

Answer

$f^{-1}(x)=-3+\sqrt{x-4}$

Question 2

Find the inverse of the function.  $f(x)=\sqrt{5x+3}$

Accepted Answer

$f^{-1}(x)=\frac{x^2-3}{5};\{x|x\geq0\}$

Answer

$f^{-1}(x)=(\frac{x}{5}-3)^2;\{x|x\geq0\}$

Answer

$f^{-1}(x)=(\frac{x-3}{5})^2;\{x|x\geq3\}$

Answer

$f^{-1}(x)=\frac{x^2}{5}-3;\{x|x\geq0\}$

Question 3

Find the inverse of the function.  $f(x)=(x-3)^3+5$

Accepted Answer

$f^{-1}(x)=\sqrt[3]{x-5}+3$

Answer

$f^{-1}(x)=\sqrt[3]{x+3}-5$

Answer

$f^{-1}(x)=\sqrt[3]{x}+2$

Answer

$f^{-1}(x)=\sqrt[3]{x}-2$

Question 4

Find the inverse of the function.  $f(x)=\frac{(-x-7)^2}{3}$

Accepted Answer

$f^{1}(x)=-7\pm\sqrt{3x}$

Answer

$f^{-1}(x)=\pm\sqrt{3x-7}$

Answer

$f^{-1}(x)=\pm\sqrt{3x+7}$

Answer

$f^{-1}(x)=7\pm\sqrt{3x}$

Question 5

Find the inverse of the function.  $f(x)=4x^3-1$

Accepted Answer

$f^{-1}(x)=\sqrt[3]\frac{x+1}{4}$

Answer

$f^{-1}(x)=\sqrt[3]\frac{x}{-4}+1$

Answer

$f^{-1}(x)=\sqrt[3]\frac{x}{4}+1$

Answer

$f^{-1}(x)=\frac{\sqrt[3]{x^2+1}}{4}$

Question 6

Find the inverse of the function.  $f(x)=3\sqrt{x-7}-4$

Accepted Answer

$f^{-1}(x)=\frac{(x+4)^2}{9}+7;\{x|x\geq-4\}$

Answer

$f^{-1}(x)=\frac{(x+3)^2}{7}+4;\{x|x\geq3\}$

Answer

$f^{-1}(x)=\frac{(x+7)^2}{3}+4;\{x|x\geq-7\}$

Answer

$f^{-1}(x)=\frac{(x+4)^2}{3}+7;\{x|x\geq4\}$

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