LAB_TEST FOR NUCLEIC ACIDS (FINALS)
Quiz by Angelo Carlo Gulanes
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- Q1
Yeast cells contain a substantial amount of RNA. RNA is a critical nucleic acid involved in various cellular processes, including protein synthesis and gene expression. The abundance of RNA in yeast makes it a convenient source for isolation and analysis. Considering the above information, what role does RNA play in cellular processes?
Critical for protein synthesis and gene expression.
Primarily responsible for cell structure.
Essential for energy production.
Limited involvement in cellular processes.
60s - Q2
Yeast cells contain a substantial amount of RNA. RNA is a critical nucleic acid involved in various cellular processes, including protein synthesis and gene expression. The abundance of RNA in yeast makes it a convenient source for isolation and analysis. Considering the above information, Why is the abundance of RNA in yeast emphasized?
To emphasize its structural significance.
To underscore its function in various cellular processes.
To indicate its secondary importance in cell function.
To highlight its role in energy storage.
60s - Q3
Yeast cells contain a substantial amount of RNA. RNA is a critical nucleic acid involved in various cellular processes, including protein synthesis and gene expression. The abundance of RNA in yeast makes it a convenient source for isolation and analysis. In the context of RNA abundance in yeast, what makes yeast a convenient source for isolation and analysis?
Exclusive presence of ribosomal RNA.
High quantity of RNA.
Limited variation in RNA types.
Low significance in cellular functions.
30s - Q4
Yeast cells contain a substantial amount of RNA. RNA is a critical nucleic acid involved in various cellular processes, including protein synthesis and gene expression. The abundance of RNA in yeast makes it a convenient source for isolation and analysis. What cellular processes benefit directly from the substantial amount of RNA in yeast cells?
Cellular respiration.
Cell division.
DNA replication.
Due to its simple cell structure.
60s - Q5
Yeast cells contain a substantial amount of RNA. RNA is a critical nucleic acid involved in various cellular processes, including protein synthesis and gene expression. The abundance of RNA in yeast makes it a convenient source for isolation and analysis. Why is yeast regarded as a convenient source for RNA isolation and analysis?
In spite of its low RNA quantity.
Due to its simple cell structure
Because of its complexity in cellular processes.
Owing to its minimal RNA content.
60s - Q6
Mild Acid Hydrolysis: Before adding Bial's reagent, it's common to perform mild acid hydrolysis. This step involves adding a mild acid, such as hydrochloric acid (HCl), to the solution. The purpose of this hydrolysis is to break down any larger polysaccharides or disaccharides into their constituent monosaccharides. In the case of ribose, which is a pentose (a type of monosaccharide), this step ensures that any ribose present in more complex structures is liberated. What is the primary purpose of mild acid hydrolysis in the context of ribose extraction?
To convert ribose into a disaccharide.
To prevent the liberation of ribose from larger structures.
To facilitate the breakdown of polysaccharides into monosaccharides.
To enhance the complexity of ribose structures.
60s - Q7
Mild Acid Hydrolysis: Before adding Bial's reagent, it's common to perform mild acid hydrolysis. This step involves adding a mild acid, such as hydrochloric acid (HCl), to the solution. The purpose of this hydrolysis is to break down any larger polysaccharides or disaccharides into their constituent monosaccharides. In the case of ribose, which is a pentose (a type of monosaccharide), this step ensures that any ribose present in more complex structures is liberated. How does the hydrolysis of larger polysaccharides during mild acid hydrolysis contribute to the availability of ribose for extraction?
It hinders the availability of ribose.
It transforms ribose into disaccharides.
It releases ribose from larger structures, making it available for extraction.
It has no impact on ribose availability.
60s - Q8
Mild Acid Hydrolysis: Before adding Bial's reagent, it's common to perform mild acid hydrolysis. This step involves adding a mild acid, such as hydrochloric acid (HCl), to the solution. The purpose of this hydrolysis is to break down any larger polysaccharides or disaccharides into their constituent monosaccharides. In the case of ribose, which is a pentose (a type of monosaccharide), this step ensures that any ribose present in more complex structures is liberated. Why is it essential to perform mild acid hydrolysis before adding Bial's reagent in ribose extraction?
To prevent the breakdown of polysaccharides.
To convert ribose into disaccharides.
To break down larger polysaccharides into monosaccharides.
To create a more acidic environment.
60s - Q9
Mild Acid Hydrolysis: Before adding Bial's reagent, it's common to perform mild acid hydrolysis. This step involves adding a mild acid, such as hydrochloric acid (HCl), to the solution. The purpose of this hydrolysis is to break down any larger polysaccharides or disaccharides into their constituent monosaccharides. In the case of ribose, which is a pentose (a type of monosaccharide), this step ensures that any ribose present in more complex structures is liberated. What role does mild acid hydrolysis play specifically in liberating ribose during the extraction process?
It selectively converts ribose into glucose.
It promotes the formation of larger polysaccharide structures.
It ensures the release of ribose from more complex structures.
It facilitates the breakdown of all types of sugars uniformly.
60s - Q10
Mild Acid Hydrolysis: Before adding Bial's reagent, it's common to perform mild acid hydrolysis. This step involves adding a mild acid, such as hydrochloric acid (HCl), to the solution. The purpose of this hydrolysis is to break down any larger polysaccharides or disaccharides into their constituent monosaccharides. In the case of ribose, which is a pentose (a type of monosaccharide), this step ensures that any ribose present in more complex structures is liberated. How does the formation of a visible color change in the solution during mild acid hydrolysis signify the success of ribose liberation?
The color change indicates the presence of disaccharides.
The color change indicates the release of ribose from larger structures.
The color change signals the absence of ribose.
The color change is unrelated to ribose liberation.
60s - Q11
In the presence of inorganic phosphates, ammonium molybdate reacts to form a yellow phosphomolybdic acid complex. This complex precipitates out of the solution, giving a visible yellow coloration. What specific color change is observed in the solution when the phosphomolybdic acid complex precipitates due to the presence of inorganic phosphates?
Green
Yellow
Red
Blue
60s - Q12
In the presence of inorganic phosphates, ammonium molybdate reacts to form a yellow phosphomolybdic acid complex. This complex precipitates out of the solution, giving a visible yellow coloration. How does the formation of a yellow phosphomolybdic acid complex indicate the presence of inorganic phosphates in the solution?
Phosphomolybdic acid only forms in the absence of inorganic phosphates.
The yellow color is a specific indicator of the presence of inorganic phosphates.
The solution remains colorless even in the presence of phosphates.
The yellow coloration is unrelated to phosphate detection.
60s - Q13
Why is the precipitation of the yellow phosphomolybdic acid complex significant in the context of detecting inorganic phosphates?
It changes the solution color to blue.
It interferes with the accuracy of the phosphate detection process.
It provides a visible indication of the presence of inorganic phosphates.
The precipitation occurs only in the absence of phosphates.
30s - Q14
What is the role of ammonium molybdate in the formation of the yellow phosphomolybdic acid complex?
Ammonium molybdate reacts with inorganic phosphates to form a yellow complex.
Ammonium molybdate initiates the precipitation process.
Ammonium molybdate prevents the formation of the complex.
Ammonium molybdate reacts with inorganic phosphates to form a blue complex.
30s - Q15
What does the visible yellow coloration of the solution signify in terms of the chemical interaction involving inorganic phosphates and ammonium molybdate?
It indicates the absence of inorganic phosphates.
The yellow color signals the formation of phosphoric acid.
The yellow color is unrelated to the chemical reaction.
The yellow color signals the formation of the phosphomolybdic acid complex due to inorganic phosphates.
30s