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Operating System Final Exam (2-BSIT-1)
Quiz by Brianne M. Singson
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- Q1
In this Scheduling Algorithm, the process that has the smallest next CPU burst will be assigned to the CPU if available.
SJFS
FCFS
Priority Scheduling
Round Robin
60s - Q2
Using the first come first serve algorithm, assuming that all processes arrive at time 0, calculate the average waiting time of these processes considering the burst time of each process is equal to P1 = 2, P2 = 3, and P3 = 5.
1.66
10
3.33
2.33
300s - Q3
A major problem in priority scheduling is indefinite blocking, also known as ________________ which can leave some low-priority processes waiting indefinitely.
Users re-arrange answers into correct orderJumble60s - Q4
Connect the following :
Users link answersLinking120s - Q5
Arrange the following steps in order to compute the average waiting time in Round Robin Algorithm.
Users link answersLinking120s - Q6
In method 2 of the Round Robin Algorithm, we can compute both average waiting time and average turnaround time.
falsetrueTrue or False60s - Q7
Shortest-Job-First Scheduling can be either preemptive or nonpreemptive
truefalseTrue or False60s - Q8
Preemptive scheduling in SJFS means that the arrival time is NOT considered and focuses only on the length of the process.
falsetrueTrue or False60s - Q9
Considering the process listed, which of the following two processes will be processed first using the SJFS Algorithm in preemptive mode?
P1 followed by P3
P2 followed by P1
P1 followed by P2
P3 followed by P4
120s - Q10
When using the round-robin scheduling, how many interrupts could the P1 process encounter if the time quantum = 4?
1
2
3
4
300s - Q11
Considering the round-robin algorithm with a time quantum of 4, at what time will P4 will be finished processing?
8
20
12
18
300s - Q12
Considering the round-robin algorithm with a time quantum of 4, at what time will P3 start to be processed?
7
10
16
8
300s - Q13
In the SJFS Algorithm, which of the following process will be processed first?
P3 with a burst time of 2
P1 with a burst time of 3
P2 with a burst time of 4
P4 with a burst time of 2
60s - Q14
Using the priority scheduling algorithm, which process will be the first to be finished and why?
P5, because it has the highest priority value.
P1, because it is the first to be processed.
P4, because it has the least burst time value.
P3, because it has the first priority value.
120s - Q15
Using the priority scheduling algorithm, P2 and P5 have the same burst time of 5, which among the two processes will be the first to be processed and why?
P5, because it has the highest process ID.
P2, because it has the highest priority value.
P2, because it has the lowest process ID.
P5, because it has the highest priority value.
120s