P4.B Progress Check 5
Quiz by ALEJANDRO URBY
High School
Physics (2017)
Texas Essential Knowledge and Skills (TEKS)
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- Q 1/5Score 0What given information can be found in this problem?29vi=0m/s, a=850m/s^2, t=0.5svi=0m/s, a=850m/s^2, t=9.8svi=0m/s, a=-9.8m/s^2, t=0.5svi=-9.8m/s, a=850m/s^2, t=0.5s
5 questions
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- Q1What given information can be found in this problem?vi=0m/s, a=850m/s^2, t=0.5svi=0m/s, a=850m/s^2, t=9.8svi=0m/s, a=-9.8m/s^2, t=0.5svi=-9.8m/s, a=850m/s^2, t=0.5s120s112.39.c.4.b
- Q2If you are looking for the distance what equation would you use?d=vi*t+(1/2)a*t^2v=d/ta=(vf-vi)/ta=(vf^2-vi^2)/2d120s112.39.c.4.b
- Q3How far will it go in this time?d=900md=425md=230md=106.25m120s112.39.c.4.b
- Q4If you had been given the final velocity instead of time in the problem what equation would you have been able to use to solve for displacement?a=(vf-vi)/ta=(vf^2-vi^2)/2dv=d/td=vi*t+(1/2)a*t^2120s112.39.c.4.b
- Q5What would the position vs time graph look like for the motion of this object?Curved line with a positive decreasing slopeStraight line with a positive constant slopeCurved line with a positive increasing slopeFlat line120s112.39.c.4.b
