P4.C Progress Check 2 | Quizalize

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P4.C Progress Check 2

Quiz by ALEJANDRO URBY

High School

Physics (2017)

Texas Essential Knowledge and Skills (TEKS)

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High School
Physics (2017)
Texas Essential Knowledge and Skills (TEKS)

112.39.c.4.c

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Q 1/5
Score 0
What variables are given and implied in the above situation?
29

v(ix)=14m/s, t=2s, v(iy)=0m/s, a(x)=0m/s^2, a(y)=-9.8m/s^2
Pick the other choice. We are given the initial horizontal velocity and the time. The variables that are implied are the initial vertical velocity (0m/s because it was launched horizontally, not verticaly), the horizontal acceleration (0m/s^2 because there is no horizontal force after it is in the air), the vertical acceleration (-9.8m/s^2 because of gravity).

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5 questions

Show answers

Q1
What variables are given and implied in the above situation?
v(ix)=14m/s, t=2s, v(iy)=0m/s, a(x)=0m/s^2, a(y)=-9.8m/s^2
Pick the other choice. We are given the initial horizontal velocity and the time. The variables that are implied are the initial vertical velocity (0m/s because it was launched horizontally, not verticaly), the horizontal acceleration (0m/s^2 because there is no horizontal force after it is in the air), the vertical acceleration (-9.8m/s^2 because of gravity).
120s
112.39.c.4.c
Q2
What equation is necessary to solve for the horizontal displacement of the baseball as it lands if we know what v(ix), a(x), and t is?
a=(vf-vi)/t
d=v(ix)*t+(1/2)a(x)*t^2
a=(vf^2-vi^2)/2d
v=d/t
120s
112.39.c.4.c
Q3
Which of the following quantities was constant while the baseball was in the air?
Acceleration
Velocity
Position
Displacement
120s
112.39.c.4.c
Q4
Calculate the displacement of the ball after it lands.
20m
24m
9.8m
28m
120s
112.39.c.4.c
Q5
What would a graph of acceleration vs. time for the horizontal component of the ball’s motion look like?
Flat line on 0m/s^2
Straight line with a positive slope
Straight line with a negative slope
Flat line on -9.8m/s^2
120s
112.39.c.4.c