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5 questions
Show answers
  • Q1
    Identify the variables in the above situation.
    Question Image
    V=12.0V, R1=10 Ohms, R2=10 Ohms
    V=12.0V, Rtot=10 Ohms
    I=12.0V, R1=10 Ohms, R2= 10 Ohms
    V=10.0V, R1=12 Ohms, R2=12 Ohms
    120s
    112.39.c.5.f
  • Q2
    What equation can be used to calculate the current in the circuit?
    Question Image
    V=IR
    Rp=(1/R1+1/R2+1/Rn)^-1
    F=ma
    Rs=R1+R2+Rn
    120s
    112.39.c.5.f
  • Q3
    What is the current running through the first resistor?
    Question Image
    120A
    240A
    0.6A
    1.7A
    120s
    112.39.c.5.f
  • Q4
    If the two resistors are rearranged so that they are parallel in the circuit, what would be the current flowing out of the battery?
    Question Image
    2.4A
    0.4A
    60A
    1.2A
    120s
    112.39.c.5.f
  • Q5
    If the two resistors are still in parallel, what would be the current flowing through each resistor?
    Question Image
    2.4A
    60A
    1.2A
    0.4
    120s
    112.39.c.5.f

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