Quadrilateral that are parallelogram

Two diagonals bisect each other.

Two pairs of sides are parallel.

Two pairs of opposite sides are congruent.

Two angles are supplementary.

$\backslash angle\; X$ is a right angle

$\backslash overline\{WX\}\backslash \; \backslash cong\backslash \; \backslash overline\{YZ\}$

$\backslash overline\{WX\}\backslash \; \backslash parallel\backslash \; \backslash overline\{YZ\}$

$\backslash overline\{WX\}\backslash \; \backslash \; and\backslash \; \backslash overline\{YZ\}\backslash \; bi\backslash sec\; t\backslash \; each\backslash \; other$

x = 7; NM = 20; OL = 22

x =5; NM = 20; OL = 20

x = 7; NM = 22; OL = 22

x= 5; NM = 22; OL = 20

No, you cannot prove that the quadrilateral is a parallelogram.

Yes, opposite sides are congruent.

Yes, opposite angles are congruent.

Yes, two opposite sides are both parallel and congruent.

No, you cannot determine that the quadrilateral isa parallelogram.

Yes, two opposite sides are both parallel andcongruent.

Yes, diagonals of a parallelogram bisect each other.

Yes, opposite sides are congruent.

$\backslash Delta$GMH must be congruent to IMF.

$\backslash Delta$HGI must be an acute triangle.

$\backslash Delta$FMG must be congruent to HMG.

$\backslash Delta$FGHI must be an obtuse triangle.      

Parallel lines have congruent corresponding angles.

Corresponding parts of congruent triangles are congruent.

 Alternate interior angles in congruent triangles are congruent.

Oppositeangles in a quadrilateral are congruent.