Calculate the heat needed to turn 100 g of ice from -5°C to steam at 100°C. (Use c=2100 J/kg⋅Kc = 2100 \, J/kg \cdot Kc=2100J/kg⋅K for ice, c=4186 J/kg⋅Kc = 4186 \, J/kg \cdot Kc=4186J/kg⋅K for water, Lfusion=333×103 J/kgL_{fusion} = 333 \times 10^3 \, J/kgLfusion​=333×103J/kg, and Lvaporization=2.3×106 J/kgL_{vaporization} = 2.3 \times 10^6 \, J/kgLvaporization​=2.3×106J/kg)