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QUIZ # 5

Quiz by Joymmy Salvador

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Q 1/5
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29

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5 questions

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Q1
60s
Q2
NUMBER 2: Based from question no. 1, what trigonometric ratio are we need to use in the given problem?
$\tan\theta=\frac{opposite}{hypotenuse}$
$\cos\theta=\frac{adjacent}{hypotenuse}$
$\sin\theta=\frac{opposite}{hypotenuse}$
30s
Q3
30s
Q4
30s
Q5
30s

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