Quiz-Statistics & Probability-Week 4.2
Quiz by Kimberly Mae Isaac
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10 questions
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- Q1Suppose the average time required to process the customers’ transaction in Landbank Meycauayan is 15 minutes with a standard deviation 5 minutes. If the processing time is normally distributed, what is the probability that the customer chosen at random will finish his/ her transaction in less than 10 minutes?15.87%34.13%84.13%65.87%120s
- Q2Given X = 25, μ = 15, σ = 3, compute for the z-score.z = 3.33z = 1.47X = - 1.47z = - 3.3345s
- Q3Given z = 2.00, μ = 34, σ = 3, what is the value of the normal random variable (X)?X = -28X = 71X = 40X = 6545s
- Q4Given z = 2.50, μ = 23, σ = 2, what is the value of the normal random variable (X)?X = 55.50X = 59.50X = - 18X = 2845s
- Q5Given X = 35, μ = 45, σ = 5, compute for the z-score.z = 0.67X = - 0.67z = 2.00z = - 2.0045s
- Q6Given X = 54, μ = 60, σ = 10, compute for the z-score.z = 0.73z = 0.60z = - 0.60X = - 0.7345s
- Q7Express this statement in Probability Notation: The probability that the z-score is below z = 2.36.P (z < 2.36)P (z = 2.36)P (z > 2.36P (0 < z < 2.36)30s
- Q8Find the area at least z = -1.55.P (z>-1.55) = 0.0606P (z>-1.55) = 0.4394P (z>-1.55) = 0.9394P (z>-1.55) = - 0.060660s
- Q9Find the area at most z = 2.01.P (z<2.01) = 0.0222P (z<2.01) = 0.5222P (z<2.01) = 0.4778P (z<2.01) = 0.977860s
- Q10Express this statement in Probability Notation: The probability that the z-score is between -1.43 & -3.01.P (z = 2.36)P (-3.01 < z < -1.43)P (z > 2.36P (0 < z < 2.36)30s