Review and Remediation Cell Organelles, Functions and Transport
Quiz by Katheryn Eubanks
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- Q 1/28Score 0
If an egg is soaked in vinegar for two days then salt water for two days, what factor explains why the egg's size changed during the experiment?
29The egg was selectively permeable, and liquids diffused in and out of the egg by osmosis.
The egg was slightly shriveled on day 5 because it was placed in a hypotonic solution.
The egg could not undergo osmosis because it was placed in different solutions.
On day 3 the egg was the smallest because the shell had dissolved off of the egg
- Q1
If an egg is soaked in vinegar for two days then salt water for two days, what factor explains why the egg's size changed during the experiment?
The egg was selectively permeable, and liquids diffused in and out of the egg by osmosis.
The egg was slightly shriveled on day 5 because it was placed in a hypotonic solution.
The egg could not undergo osmosis because it was placed in different solutions.
On day 3 the egg was the smallest because the shell had dissolved off of the egg
30sSB1d - Q2
Phagocytosis, or cellular eating, occurs when the dissolved materials enter the cell.
Pinocytosis, or cellular drinking, occurs when the plasma membrane folds inward to form a channel allowing dissolved substances to enter the cell. BOTH THESE ARE EXAMPLES OF ___.
Endocytosis
Diffusion
Mitosis
Exocytosis
30sSB1d - Q3
The image shows plant cells. What is represented by plant cell C?
Plant cell C was most likely placed in a hypotonic solution and underwent osmosis where it became turgid.
Plant cell C was likely placed in a isotonic solution and is perfect.
Plant cell C was most likely placed in a hypotonic solution and took in lots of water.
Plant cell C was most likely placed in a hypertonic solution and underwent osmosis where it plasmolyzed.
30sSB1d - Q4
Beaker B shows a red blood cell placed in a solution that is causing the water to leave the cell. Why is this happening?
This is endocytosis and the red blood cells are releasing water because they have been placed in a hypertonic solution.
This is osmosis and the red blood cells are releasing water because they have been placed in a hypotonic solution.
This is diffusion and the red blood cells are releasing water because they have been placed in a hypertonic solution.
This is osmosis and the red blood cells are releasing water because they have been placed in a hypertonic solution.
30sSB1d - Q5
Observe beaker A, what is the best explanation for what is happening?
The red blood cell is undergoing diffusion and is about to burst.
The red blood cell is undergoing osmosis and is in a isotonic solution which means both the concentration of solute and water are equal.
The red blood cell is undergoing osmosis and is in a hypotonic solution which means both the concentration of solute and water are equal.
The red blood cell is undergoing osmosis and is in a hypertonic solution.
30sSB1d - Q6
Looking at the image, explain what is happening in Beaker C.
Water is released out of the cell because it is in a hypertonic solution through osmosis
Water is absorbed through osmosis which does not require energy
Water is released through osmosis which does require energy
Water is absorbed because it is in a hypertonic solution through osmosis
30sSB1d - Q7
What is represented by the diagram?
Active Transport which requires energy
Active Transport which does not require energy
Passive Transport which requires energy
Passive Transport which does not require energy
30sSB1d - Q8
In the diagram, the cell on the right is plasmolyzed and the cell on the left is turgid. What does this mean and under what conditions would it be in this condition?
The cells have all been placed in a hypertonic solution and they are dying.
The cell on the left was placed in a hypertonic solution so it released water and shrank; the cell on the right was placed in a hypotonic solution so it absorbed water
The cell on the right was placed in a isotonic solution so it released water and shrank; the cell on the left was placed in a hypertonic solution so it absorbed water
The cell on the right was placed in a hypertonic solution so it released water and shrank; the cell on the left was placed in a hypotonic solution so it absorbed water
30sSB1d - Q9
The movement of solute molecules from an area of high concentration to low concentration is an example of
Diffusion which is Passive Transport
Diffusion which is Active Transport
Osmosis which is Passive Transport
Osmosis which is Active Transport
30sSB1d - Q10
A biologist observed a plant cell in a drop of water as shown in diagram A. The biologist added a 10% salt solution to the slide and observed the cell as shown in diagram B. The change in appearance of the cell resulted from
more salt moving out of the cell than into the cell
more water moving out of the cell than into the cell
more salt moving into the cell than out of the cell
more water moving into the cell than out of the cell
30sSB1d - Q11
When a molecule enters a cell with the help of proteins of its membrane, it has undergone
Adhesion which is passive transport
Osmosis which is active transport
facilitated diffusion which is passive transport
facilitated diffusion which is active transport
30sSB1d - Q12
In the diagram, the dark dots indicate small molecules. These molecules are moving out of the cells, as indicated by the arrows. The number of dots inside and outside of the two cells represents the relative concentrations of the molecules inside and outside of the cells.
ATP is being used to move the molecules out of the cell by
both Cell A and Cell B
Neither Cell A nor Cell B
Cell B, only
Cell A, only
30sSB1d - Q13
When placed in water wilted plants regain their leaf turgor because of the
active transport of salts from the water into the plant cells
osmosis of water into the plant cells
active transport of salts from the plant cells into the water
osmosis of water out of the plant cells
diffusion of water out of the plant cells
30sSB1d - Q14
The picture shows a wilted plant. What can be assumed about the cells of this plant?
The stems of the plant have broken and can no longer support the weight of the leaves.
The plant has taken in too much water and its cells have plasmolyzed
Many cells within the plant have lost water and are no longer turgid
Many cells within the plant have died and are no longer multiplying.
30sSB1d - Q15
Look at the U-tube below, the left side is a hypotonic solution and the right side is a hypertonic solution. What can you predict will happen after a period of time?
The water is equal on both sides and will never change
The water will stay the same, but the solute molecules will move through the semi-permeable membrane.
The hypertonic solution will move from low to high concentration because this represents diffusion
Osmosis will occur, the water on the left will flow through the semi-permeable membrane toward the higher concentration of solute.
30sSB1d
