Six Trigonometric Ratios

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25 questions
• Q1
120s
• Q2
120s
• Q3
cos 87
.05
.0523
.5700
.569
900s
• Q4
What is the correct ratio?
$\frac{8}{6}$
$\frac{6}{10}$
$\frac{6}{8}$
$\frac{8}{10}$
30s
• Q5
What is the correct equation to solve for x?
$\tan45\degree=\frac{x}{13}$
$\sin45\degree=\frac{13}{x}$
$\sin\ 45\degree=\frac{x}{13}$
$\cos45\degree=\frac{x}{13}$
30s
• Q6
What is the length of the hypotenuse side?
8
17
15
30s
• Q7
Find the measure of the missing angle.
41o
49o
33o
50o
180s
• Q8
Choose the correct ratio.
$\tan\ Z=\frac{12}{5}$
$\sin\ Z=\frac{5}{13}$
$\sin\ X=\frac{5}{13}$
$\cos\ X=\frac{12}{13}$
45s
• Q9
What is the correct ratio for tan A?
$\frac{20}{12}$
$\frac{12}{20}$
$\frac{16}{12}$
$\frac{12}{16}$
30s
• Q10
30s
• Q11
What is the formula for secant?
$\sec=\frac{opposite}{hypotenuse}$
$\sec=\frac{adjacent}{opposite}$
$\sec=\frac{hypotenuse}{adjacent}$
$\sec=\frac{hypotenuse}{opposite}$
30s
• Q12
What is the formula for cosecant?
$\csc=\frac{opposite}{hypotenuse}$
$\csc=\frac{adjacent}{opposite}$
$\csc=\frac{hypotenuse}{opposite}$
30s
• Q13
what is the formula for cotangent
cot⁡=oppositehypotenuse\cot=\frac{opposite}{hypotenuse}cot=hypotenuseopposite​
$\cot=\frac{hypotenuse}{adjacent}$
$\cot=\frac{hypotenuse}{opposite}$
30s
• Q14
Find the measure of the missing angle.
50o
33o
49o
41o
300s
• Q15
Identify side XZ, with respect to the marked angle.
hypotenuse
altitude
opposite