Six Trigonometric Ratios
Quiz by Patrick Morgado
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25 questions
Show answers
- Q1120s
- Q2120s
- Q3cos 87.05.0523.5700.569900s
- Q4What is the correct ratio?$\frac{8}{6}$$\frac{6}{10}$$\frac{6}{8}$$\frac{8}{10}$30s
- Q5What is the correct equation to solve for x?$\tan45\degree=\frac{x}{13}$$\sin45\degree=\frac{13}{x}$$\sin\ 45\degree=\frac{x}{13}$$\cos45\degree=\frac{x}{13}$30s
- Q6What is the length of the hypotenuse side?8171530s
- Q7Find the measure of the missing angle.41o49o33o50o180s
- Q8Choose the correct ratio.$\tan\ Z=\frac{12}{5}$$\sin\ Z=\frac{5}{13}$$\sin\ X=\frac{5}{13}$$\cos\ X=\frac{12}{13}$45s
- Q9What is the correct ratio for tan A?$\frac{20}{12}$$\frac{12}{20}$$\frac{16}{12}$$\frac{12}{16}$30s
- Q1030s
- Q11What is the formula for secant?$\sec=\frac{opposite}{hypotenuse}$$\sec=\frac{adjacent}{opposite}$$\sec=\frac{hypotenuse}{adjacent}$$\sec=\frac{hypotenuse}{opposite}$30s
- Q12What is the formula for cosecant?$\csc=\frac{opposite}{hypotenuse}$$\csc=\frac{adjacent}{opposite}$$\csc=\frac{hypotenuse}{opposite}$csc=hypotenuseadjacent\csc=\frac{hypotenuse}{adjacent}csc=adjacenthypotenuse30s
- Q13what is the formula for cotangentcot=oppositehypotenuse\cot=\frac{opposite}{hypotenuse}cot=hypotenuseopposite$\cot=\frac{hypotenuse}{adjacent}$cot=adjacentopposite\cot=\frac{adjacent}{opposite}cot=oppositeadjacent$\cot=\frac{hypotenuse}{opposite}$30s
- Q14Find the measure of the missing angle.50o33o49o41o300s
- Q15Identify side XZ, with respect to the marked angle.hypotenusealtitudeoppositeadjacent30s
