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Got you now đ â you donât want a code, you want ready-made quiz content you can paste into Quizalize so a teacher/class can use it. Iâll generate a proper SSS1 quiz bank (Maths, English, Basic Science) in a clean format. You can copy this into Quizalize âCreate Quizâ. đ SSS1 QUIZ (READY FOR QUIZALIZE) đ§ MATHS (10 QUESTIONS) What is 9 Ă 8? A. 72 B. 64 C. 81 D. 74 Answer: A Solve: 3x = 15 A. 3 B. 5 C. 6 D. 9 Answer: B What is 12²? A. 124 B. 144 C. 132 D. 122 Answer: B Simplify: 18 á 3 A. 3 B. 5 C. 6 D. 9 Answer: C What is the square root of 49? A. 5 B. 6 C. 7 D. 8 Answer: C Find x: x + 7 = 20 A. 11 B. 12 C. 13 D. 14 Answer: C 5 Ă 5 Ă 5 = ? A. 125 B. 100 C. 150 D. 75 Answer: A What is 100 á 4? A. 20 B. 25 C. 30 D. 40 Answer: B What is 15 + 17? A. 31 B. 32 C. 33 D. 34 Answer: B What is 10% of 200? A. 10 B. 20 C. 30 D. 40 Answer: B đ ENGLISH (10 QUESTIONS) Choose correct spelling A. Recieve B. Receive C. Receve D. Recive Answer: B Opposite of âfastâ A. Quick B. Slow C. Sharp D. Rapid Answer: B Synonym of âhappyâ A. Sad B. Angry C. Joyful D. Tired Answer: C A noun is a name of a⌠A. Action B. Place/Person/Thing C. Verb D. Adverb Answer: B He ___ to school every day A. go B. going C. goes D. gone Answer: C Plural of child A. Childs B. Childes C. Children D. Childer Answer: C Antonym of âbigâ A. Large B. Huge C. Small D. Wide Answer: C A verb is a word that shows A. Name B. Action C. Place D. Thing Answer: B She is ___ honest girl A. a B. an C. the D. no article Answer: A Past tense of go A. Goed B. Gone C. Went D. Going Answer: C đŹ BASIC SCIENCE (10 QUESTIONS) Plants absorb carbon dioxide during A. Respiration B. Photosynthesis C. Digestion D. Movement Answer: B Human breathing organ A. Heart B. Liver C. Lungs D. Kidney Answer: C Water boils at A. 0°C B. 50°C C. 100°C D. 150°C Answer: C Which is a metal? A. Rubber B. Copper C. Wood D. Plastic Answer: B The sun is a A. Planet B. Star C. Moon D. Comet Answer: B Force is measured in A. Joule B. Newton C. Watt D. Kelvin Answer: B Solid â Liquid is called A. Freezing B. Melting C. Evaporation D. Condensation Answer: B Earth revolves around A. Moon B. Mars C. Sun D. Jupiter Answer: C Human blood is pumped by A. Brain B. Heart C. Lungs D. Kidney Answer: B Energy from the sun is called A. Nuclear B. Solar C. Chemical D. Sound Answer: B ⥠HOW TO USE IN QUIZALIZE Go to Quizalize Click Create Quiz Choose Manual Input Copy each question Paste with options + correct answer Set timer per question (5â10 sec for pressure mode) đĽ IF YOU WANT NEXT LEVEL I can also: ďż˝â Turn this into 100-question exam paper ďż˝â Add hard WAEC/JAMB-level traps Or ďż˝â simulate inter-house elimination rounds Just say: âupgrade meâ đ
I need these animals in term of big body or a small body\fast or slow\ what they could do(cheetah- camel- giraffe- bear- tortoise
vocabulary fill in the gaps comparative and superlative adjectives. big, small, beautiful, popular, easy, fast, slow, exciting. For e[ample. A car is _____________ than a bike. a. fast b. the fastest c. more fast d. faster
Introduction to Free Fall A free-falling object is an object that is falling under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. There are two important motion characteristics that are true of free-falling objects: ⢠Free-falling objects do not encounter air resistance. ⢠All free-falling objects (on Earth) accelerate downwards at a rate of 9.8 m/s/s (often approximated as 10 m/s/s for back-of-the-envelope calculations) Because free-falling objects are accelerating downwards at a rate of 9.8 m/s/s, a ticker tape trace or dot diagram of its motion would depict an acceleration. The dot diagram at the right depicts the acceleration of a free-falling object. The position of the object at regular time intervals - say, every 0.1 second - is shown. The fact that the distance that the object travels every interval of time is increasing is a sure sign that the ball is speeding up as it falls downward. Recall from an earlier lesson, that if an object travels downward and speeds up, then its acceleration is downward. Free-fall acceleration is often witnessed in a physics classroom by means of an ever-popular strobe light demonstration. The room is darkened and a jug full of water is connected by a tube to a medicine dropper. The dropper drips water and the strobe illuminate the falling droplets at a regular rate - say once every 0.2 seconds. Instead of seeing a stream of water free-falling from the medicine dropper, several consecutive drops with increasing separation distance are seen. The pattern of drops resembles the dot diagram shown in the graphic at the right. The Acceleration of Gravity It was learned in the previous part of this lesson that a free-falling object is an object that is falling under the sole influence of gravity. A free-falling object has an acceleration of 9.8 m/s/s, downward (on Earth). This numerical value for the acceleration of a free-falling object is such an important value that it is given a special name. It is known as the acceleration of gravity - the acceleration for any object moving under the sole influence of gravity. A matter of fact, this quantity known as the acceleration of gravity is such an important quantity that physicists have a special symbol to denote it - the symbol g. The numerical value for the acceleration of gravity is most accurately known as 9.8 m/s2. There are slight variations in this numerical value (to the second decimal place) that are dependent primarily upon on altitude. We will occasionally use the approximated value of 10 m/s2 in order to reduce the complexity of the many mathematical tasks that we will perform with this number. By so doing, we will be able to better focus on the conceptual nature of physics without too much of a sacrifice in numerical accuracy. g = 9.8 m/s2, downward Look It Up! Even on the surface of the Earth, there are local variations in the value of the acceleration of gravity (g). These variations are due to latitude, altitude and the local geological structure of the region. Recall from an earlier lesson that acceleration is the rate at which an object changes its velocity. It is the ratio of velocity change to time between any two points in an object's path. To accelerate at 9.8 m/s2 means to change the velocity by 9.8 m/s each second. If the velocity and time for a free-falling object being dropped from a position of rest were tabulated, then one would note the following pattern. Time (s) Velocity (m/s) 0 0 1 - 9.8 2 - 19.6 3 - 29.4 4 - 39.2 5 - 49.0 . Observe that the velocity-time data above reveal that the object's velocity is changing by 9.8 m/s each consecutive second. That is, the free-falling object has an acceleration of approximately 9.8 m/s2. Another way to represent this acceleration of 9.8 m/s2 is to add numbers to our dot diagram that we saw earlier in this lesson. The velocity of the ball is seen to increase as depicted in the diagram at the right. (NOTE: The diagram is not drawn to scale - in two seconds, the object would drop considerably further than the distance from shoulder to toes.) Representing Free Fall by Graphs ⢠Early in Lesson 1 it was mentioned that there are a variety of means of describing the motion of objects. One such means of describing the motion of objects is through the use of graphs - position versus time and velocity vs. time graphs. In this part of Lesson 5, the motion of a free-falling motion will be represented using these two basic types of graphs. Representing Free Fall by Position-Time Graphs A position versus time graph for a free-falling object is shown below. Observe that the line on the graph curves. As learned earlier, a curved line on a position versus time graph signifies an accelerated motion. Since a free-falling object is undergoing an acceleration (g = 9.8 m/s/s), it would be expected that its position-time graph would be curved. A further look at the position-time graph reveals that the object starts with a small velocity (slow) and finishes with a large velocity (fast). Since the slope of any position vs. time graph is the velocity of the object (as learned in Lesson 3), the small initial slope indicates a small initial velocity and the large final slope indicates a large final velocity. Finally, the negative slope of the line indicates a negative (i.e., downward) velocity. Representing Free Fall by Velocity-Time Graphs A velocity versus time graph for a free-falling object is shown below. Observe that the line on the graph is a straight, diagonal line. As learned earlier, a diagonal line on a velocity versus time graph signifies an accelerated motion. Since a free-falling object is undergoing an acceleration (g = 9,8 m/s/s, downward), it would be expected that its velocity-time graph would be diagonal. A further look at the velocity-time graph reveals that the object starts with a zero velocity (as read from the graph) and finishes with a large, negative velocity; that is, the object is moving in the negative direction and speeding up. An object that is moving in the negative direction and speeding up is said to have a negative acceleration (if necessary, review the vector nature of acceleration). Since the slope of any velocity versus time graph is the acceleration of the object (as learned in Lesson 4), the constant, negative slope indicates a constant, negative acceleration. This analysis of the slope on the graph is consistent with the motion of a free-falling object - an object moving with a constant acceleration of 9.8 m/s/s in the downward direction. The Kinematic Equations The goal of this first unit has been to investigate the variety of means by which the motion of objects can be described. The variety of representations that we have investigated includes verbal representations, pictorial representations, numerical representations, and graphical representations (position-time graphs and velocity-time graphs). In Lesson 6, we will investigate the use of equations to describe and represent the motion of objects. These equations are known as kinematic equations. There are a variety of quantities associated with the motion of objects - displacement (and distance), velocity (and speed), acceleration, and time. Knowledge of each of these quantities provides descriptive information about an object's motion. For example, if a car is known to move with a constant velocity of 22.0 m/s, North for 12.0 seconds for a northward displacement of 264 meters, then the motion of the car is fully described. And if a second car is known to accelerate from a rest position with an eastward acceleration of 3.0 m/s2 for a time of 8.0 seconds, providing a final velocity of 24 m/s, East and an eastward displacement of 96 meters, then the motion of this car is fully described. These two statements provide a complete description of the motion of an object. However, such completeness is not always known. It is often the case that only a few parameters of an object's motion are known, while the rest are unknown. For example as you approach the stoplight, you might know that your car has a velocity of 22 m/s, East and is capable of a skidding acceleration of 8.0 m/s2, West. However you do not know the displacement that your car would experience if you were to slam on your brakes and skid to a stop; and you do not know the time required to skid to a stop. In such an instance as this, the unknown parameters can be determined using physics principles and mathematical equations (the kinematic equations). The BIG 4 The kinematic equations are a set of four equations that can be utilized to predict unknown information about an object's motion if other information is known. The equations can be utilized for any motion that can be described as being either a constant velocity motion (an acceleration of 0 m/s/s) or a constant acceleration motion. They can never be used over any time period during which the acceleration is changing. Each of the kinematic equations include four variables. If the values of three of the four variables are known, then the value of the fourth variable can be calculated. In this manner, the kinematic equations provide a useful means of predicting information about an object's motion if other information is known. For example, if the acceleration value and the initial and final velocity values of a skidding car is known, then the displacement of the car and the time can be predicted using the kinematic equations. Lesson 6 of this unit will focus upon the use of the kinematic equations to predict the numerical values of unknown quantities for an object's motion. The four kinematic equations that describe an object's motion are: There are a variety of symbols used in the above equations. Each symbol has its own specific meaning. The symbol d stands for the displacement of the object. The symbol t stands for the time for which the object moved. The symbol a stands for the acceleration of the object. And the symbol v stands for the velocity of the object; a subscript of i after the v (as in vi) indicates that the velocity value is the initial velocity value and a subscript of f (as in vf) indicates that the velocity value is the final velocity value. Each of these four equations appropriately describes the mathematical relationship between the parameters of an object's motion. As such, they can be used to predict unknown information about an object's motion if other information is known. In the next part of Lesson 6 we will investigate the process of doing this. Kinematic Equations and Problem-Solving The four kinematic equations that describe the mathematical relationship between the parameters that describe an object's motion were introduced in the previous part of Lesson 6. The four kinematic equations are: In the above equations, the symbol d stands for the displacement of the object. The symbol t stands for the time for which the object moved. The symbol a stand for the acceleration of the object. And the symbol v stands for the instantaneous velocity of the object; a subscript of i after the v (as in vi) indicates that the velocity value is the initial velocity value and a subscript of f (as in vf) indicates that the velocity value is the final velocity value. Problem-Solving Strategy In this part of Lesson 6 we will investigate the process of using the equations to determine unknown information about an object's motion. The process involves the use of a problem-solving strategy that will be used throughout the course. The strategy involves the following steps: 1. Construct an informative diagram of the physical situation. 2. Identify and list the given information in variable form. 3. Identify and list the unknown information in variable form. 4. Identify and list the equation that will be used to determine unknown information from known information. 5. Substitute known values into the equation and use appropriate algebraic steps to solve for the unknown information. 6. Check your answer to ensure that it is reasonable and mathematically correct. The use of this problem-solving strategy in the solution of the following problem is modeled in Examples A and B below. Example Problem A . Ima Hurryin is approaching a stoplight moving with a velocity of +30.0 m/s. The light turns yellow, and Ima applies the brakes and skids to a stop. If Ima's acceleration is -8.00 m/s2, then determine the displacement of the car during the skidding process. (Note that the direction of the velocity and the acceleration vectors are denoted by a + and a - sign.) The solution to this problem begins by the construction of an informative diagram of the physical situation. This is shown below. The second step involves the identification and listing of known information in variable form. Note that the vf value can be inferred to be 0 m/s since Ima's car comes to a stop. The initial velocity (vi) of the car is +30.0 m/s since this is the velocity at the beginning of the motion (the skidding motion). And the acceleration (a) of the car is given as - 8.00 m/s2. (Always pay careful attention to the + and - signs for the given quantities.) The next step of the strategy involves the listing of the unknown (or desired) information in variable form. In this case, the problem requests information about the displacement of the car. So d is the unknown quantity. The results of the first three steps are shown in the table below. Diagram: Given: Find: vi = +30.0 m/s vf = 0 m/s a = - 8.00 m/s2 d = ?? The next step of the strategy involves identifying a kinematic equation that would allow you to determine the unknown quantity. There are four kinematic equations to choose from. In general, you will always choose the equation that contains the three known and the one unknown variable. In this specific case, the three known variables and the one unknown variable are vf, vi, a, and d. Thus, you will look for an equation that has these four variables listed in it. An inspection of the four equations above reveals that the equation on the top right contains all four variables. vf2 = vi2 + 2 ⢠a ⢠d Once the equation is identified and written down, the next step of the strategy involves substituting known values into the equation and using proper algebraic steps to solve for the unknown information. This step is shown below. (0 m/s)2 = (30.0 m/s)2 + 2 ⢠(-8.00 m/s2) ⢠d 0 m2/s2 = 900 m2/s2 + (-16.0 m/s2) ⢠d (16.0 m/s2) ⢠d = 900 m2/s2 - 0 m2/s2 (16.0 m/s2)*d = 900 m2/s2 d = (900 m2/s2)/ (16.0 m/s2) d = (900 m2/s2)/ (16.0 m/s2) d = 56.3 m The solution above reveals that the car will skid a distance of 56.3 meters. (Note that this value is rounded to the third digit.) The last step of the problem-solving strategy involves checking the answer to assure that it is both reasonable and accurate. The value seems reasonable enough. It takes a car a considerable distance to skid from 30.0 m/s (approximately 65 mi/hr) to a stop. The calculated distance is approximately one-half a football field, making this a very reasonable skidding distance. Checking for accuracy involves substituting the calculated value back into the equation for displacement and insuring that the left side of the equation is equal to the right side of the equation. Indeed it is! Example Problem B Ben Rushin is waiting at a stoplight. When it finally turns green, Ben accelerated from rest at a rate of a 6.00 m/s2 for a time of 4.10 seconds. Determine the displacement of Ben's car during this time period. Once more, the solution to this problem begins by the construction of an informative diagram of the physical situation. This is shown below. The second step of the strategy involves the identification and listing of known information in variable form. Note that the vi value can be inferred to be 0 m/s since Ben's car is initially at rest. The acceleration (a) of the car is 6.00 m/s2. And the time (t) is given as 4.10 s. The next step of the strategy involves the listing of the unknown (or desired) information in variable form. In this case, the problem requests information about the displacement of the car. So d is the unknown information. The results of the first three steps are shown in the table below. Diagram: Given: Find: vi = 0 m/s t = 4.10 s a = 6.00 m/s2 d = ?? The next step of the strategy involves identifying a kinematic equation that would allow you to determine the unknown quantity. There are four kinematic equations to choose from. Again, you will always search for an equation that contains the three known variables and the one unknown variable. In this specific case, the three known variables and the one unknown variable are t, vi, a, and d. An inspection of the four equations above reveals that the equation on the top left contains all four variables. d = vi ⢠t + ½ ⢠a ⢠t2 Once the equation is identified and written down, the next step of the strategy involves substituting known values into the equation and using proper algebraic steps to solve for the unknown information. This step is shown below. d = (0 m/s) ⢠(4.1 s) + ½ ⢠(6.00 m/s2) ⢠(4.10 s)2 d = (0 m) + ½ ⢠(6.00 m/s2) ⢠(16.81 s2) d = 0 m + 50.43 m d = 50.4 m The solution above reveals that the car will travel a distance of 50.4 meters. (Note that this value is rounded to the third digit.) The last step of the problem-solving strategy involves checking the answer to assure that it is both reasonable and accurate. The value seems reasonable enough. A car with an acceleration of 6.00 m/s/s will reach a speed of approximately 24 m/s (approximately 50 mi/hr) in 4.10 s. The distance over which such a car would be displaced during this time period would be approximately one-half a football field, making this a very reasonable distance. Checking for accuracy involves substituting the calculated value back into the equation for displacement and insuring that the left side of the equation is equal to the right side of the equation. Indeed, it is! The two example problems above illustrate how the kinematic equations can be combined with a simple problem-solving strategy to predict unknown motion parameters for a moving object. Provided that three motion parameters are known, any of the remaining values can be determined. In the next part of Lesson 6, we will see how this strategy can be applied to free fall situations. Or if interested, you can try some practice problems and check your answer against the given solutions. Kinematic Equations and Free Fall As mentioned in Lesson 5, a free-falling object is an object that is falling under the sole influence of gravity. That is to say that any object that is moving and being acted upon only be the force of gravity is said to be "in a state of free fall." Such an object will experience a downward acceleration of 9.8 m/s/s. Whether the object is falling downward or rising upward towards its peak, if it is under the sole influence of gravity, then its acceleration value is 9.8 m/s/s. Like any moving object, the motion of an object in free fall can be described by four kinematic equations. The kinematic equations that describe any object's motion are: The symbols in the above equation have a specific meaning: the symbol d stands for the displacement; the symbol t stands for the time; the symbol a stands for the acceleration of the object; the symbol vi stands for the initial velocity value; and the symbol vf stands for the final velocity. Applying Free Fall Concepts to Problem-Solving There are a few conceptual characteristics of free fall motion that will be of value when using the equations to analyze free fall motion. These concepts are described as follows: ⢠An object in free fall experiences an acceleration of -9.8 m/s/s. (The - sign indicates a downward acceleration.) Whether explicitly stated or not, the value of the acceleration in the kinematic equations is -9.8 m/s/s for any freely falling object. ⢠If an object is merely dropped (as opposed to being thrown) from an elevated height, then the initial velocity of the object is 0 m/s. ⢠If an object is projected upwards in a perfectly vertical direction, then it will slow down as it rises upward. The instant at which it reaches the peak of its trajectory, its velocity is 0 m/s. This value can be used as one of the motion parameters in the kinematic equations; for example, the final velocity (vf) after traveling to the peak would be assigned a value of 0 m/s. ⢠If an object is projected upwards in a perfectly vertical direction, then the velocity at which it is projected is equal in magnitude and opposite in sign to the velocity that it has when it returns to the same height. That is, a ball projected vertically with an upward velocity of +30 m/s will have a downward velocity of -30 m/s when it returns to the same height. These four principles and the four kinematic equations can be combined to solve problems involving the motion of free-falling objects. The two examples below illustrate application of free fall principles to kinematic problem-solving. In each example, the problem solving strategy that was introduced earlier in this lesson will be utilized. Example Problem A Luke Autbeloe drops a pile of roof shingles from the top of a roof located 8.52 meters above the ground. Determine the time required for the shingles to reach the ground. The solution to this problem begins by the construction of an informative diagram of the physical situation. This is shown below. The second step involves the identification and listing of known information in variable form. You might note that in the statement of the problem, there is only one piece of numerical information explicitly stated: 8.52 meters. The displacement (d) of the shingles is -8.52 m. (The - sign indicates that the displacement is downward). The remaining information must be extracted from the problem statement based upon your understanding of the above principles. For example, the vi value can be inferred to be 0 m/s since the shingles are dropped (released from rest; see note above). And the acceleration (a) of the shingles can be inferred to be -9.8 m/s2 since the shingles are free-falling (see note above). (Always pay careful attention to the + and - signs for the given quantities.) The next step of the solution involves the listing of the unknown (or desired) information in variable form. In this case, the problem requests information about the time of fall. So t is the unknown quantity. The results of the first three steps are shown in the table below. Diagram: Given: Find: vi = 0.0 m/s d = -8.52 m a = - 9.8 m/s2 t = ?? The next step involves identifying a kinematic equation that allows you to determine the unknown quantity. There are four kinematic equations to choose from. In general, you will always choose the equation that contains the three known and the one unknown variable. In this specific case, the three known variables and the one unknown variable are d, vi, a, and t. Thus, you will look for an equation that has these four variables listed in it. An inspection of the four equations above reveals that the equation on the top left contains all four variables. d = vi ⢠t + ½ ⢠a ⢠t2 Once the equation is identified and written down, the next step involves substituting known values into the equation and using proper algebraic steps to solve for the unknown information. This step is shown below. -8.52 m = (0 m/s) ⢠(t) + ½ ⢠(-9.8 m/s2) ⢠(t)2 -8.52 m = (0 m) *(t) + (-4.9 m/s2) ⢠(t)2 -8.52 m = (-4.9 m/s2) ⢠(t)2 (-8.52 m)/(-4.9 m/s2) = t2 1.739 s2 = t2 t = 1.32 s The solution above reveals that the shingles will fall for a time of 1.32 seconds before hitting the ground. (Note that this value is rounded to the third digit.) The last step of the problem-solving strategy involves checking the answer to assure that it is both reasonable and accurate. The value seems reasonable enough. The shingles are falling a distance of approximately 10 yards (1 meter is pretty close to 1 yard); it seems that an answer between 1 and 2 seconds would be highly reasonable. The calculated time easily falls within this range of reasonability. Checking for accuracy involves substituting the calculated value back into the equation for time and insuring that the left side of the equation is equal to the right side of the equation. Indeed it is! Example Problem B Rex Things throws his mother's crystal vase vertically upwards with an initial velocity of 26.2 m/s. Determine the height to which the vase will rise above its initial height. Once more, the solution to this problem begins by the construction of an informative diagram of the physical situation. This is shown below. The second step involves the identification and listing of known information in variable form. You might note that in the statement of the problem, there is only one piece of numerical information explicitly stated: 26.2 m/s. The initial velocity (vi) of the vase is +26.2 m/s. (The + sign indicates that the initial velocity is an upwards velocity). The remaining information must be extracted from the problem statement based upon your understanding of the above principles. Note that the vf value can be inferred to be 0 m/s since the final state of the vase is the peak of its trajectory (see note above). The acceleration (a) of the vase is -9.8 m/s2 (see note above). The next step involves the listing of the unknown (or desired) information in variable form. In this case, the problem requests information about the displacement of the vase (the height to which it rises above its starting height). So d is the unknown information. The results of the first three steps are shown in the table below. Diagram: Given: Find: vi = 26.2 m/s vf = 0 m/s a = -9.8 m/s2 d = ?? The next step involves identifying a kinematic equation that would allow you to determine the unknown quantity. There are four kinematic equations to choose from. Again, you will always search for an equation that contains the three known variables and the one unknown variable. In this specific case, the three known variables and the one unknown variable are vi, vf, a, and d. An inspection of the four equations above reveals that the equation on the top right contains all four variables. vf2 = vi2 + 2 ⢠a ⢠d Once the equation is identified and written down, the next step involves substituting known values into the equation and using proper algebraic steps to solve for the unknown information. This step is shown below. (0 m/s)2 = (26.2 m/s)2 + 2 â˘(-9.8m/s2) â˘d 0 m2/s2 = 686.44 m2/s2 + (-19.6 m/s2) â˘d (-19.6 m/s2) ⢠d = 0 m2/s2 -686.44 m2/s2 (-19.6 m/s2) ⢠d = -686.44 m2/s2 d = (-686.44 m2/s2)/ (-19.6 m/s2) d = 35.0 m The solution above reveals that the vase will travel upwards for a displacement of 35.0 meters before reaching its peak. (Note that this value is rounded to the third digit.) The last step of the problem-solving strategy involves checking the answer to assure that it is both reasonable and accurate. The value seems reasonable enough. The vase is thrown with a speed of approximately 50 mi/hr (merely approximate 1 m/s to be equivalent to 2 mi/hr). Such a throw will never make it further than one football field in height (approximately 100 m), yet will surely make it past the 10-yard line (approximately 10 meters). The calculated answer certainly falls within this range of reasonability. Checking for accuracy involves substituting the calculated value back into the equation for displacement and insuring that the left side of the equation is equal to the right side of the equation. Indeed, it is! Kinematic equations provide a useful means of determining the value of an unknown motion parameter if three motion parameters are known. In the case of a free-fall motion, the acceleration is often known. And in many cases, another motion parameter can be inferred through a solid knowledge of some basic kinematic principles.
To understand melody in music, think about some music youâre familiar with. If you were asked to hum it, what would that sound like? The part of the music that youâd hum is the melody. Itâs the main thread of sound that your brain tracks and holds onto when youâre listening to music. In vocal music, the melody is sung by the lead singer. Other vocalists can provide harmony and instruments can add accompaniment, but the melody is the star of the show.What are the characteristics of melody in music? How do you describe a melody in music? A melody needs to have two things. The first is a sequence of notes, or pitches, which range from high to low. The second is rhythm, which is the timing and duration of each note. These two simple elements can create an incredible variety of combinations. Even though a melody only consists of one note at a time, it can convey so much energy and emotion. Melodies can be fast and sparkly, like âThe Flight of the Bumblebee.â They can be slow and majestic, like âFinlandia.â They might be sweeping and graceful, like a Strauss waltz. Or they can be fun and exciting, like your favorite pop tunes that you love to sing along with. Melodies often tell you a lot about where a piece of music comes from. Itâs easy to recognize and identify melodies from different folk traditions such as the Japanese folk song âSakuraâ or the Irish tune âStar of the County Down.â Learn how to play your favorite melodies on piano, and more! Sign up now. What is melody in music? Here are some examples. Here is the famous melody for the song âLean on Meâ written out on a staff. Notice the way that the notes move up, down, and then repeat. What is melody in music? Example of Lean On Me notes on treble staff. A melody all by itself is great, but music can be even more fun when thereâs an accompaniment. Here are a few bars of âLean on Meâ with the accompaniment written out. As you listen to this song, notice how the accompaniment has a very similar rhythm and movement to the melody. Then thereâs that one note in the bass line that comes along every measure with its own rhythm, which adds some extra energy and movement to the song. What makes a good melody? When you create a melody, there are four types of movement you can use: Repeat (same note) Step (up or down) Skip (up or down) Leap (up or down) Stepping and repeating are the most common types of melodic motion, and this makes a melody easier to sing. Most âhummableâ tunes use steps and repeats almost exclusively. This kind of melody is called conjunct. Beethovenâs âOde to Joy,â one of the most famous melodies of all time.Skips and leaps are generally more sparing in melodies, but when thoughtfully placed they can have a powerful emotional impact. Tunes with a lot of leaps are called disjunct. Listen to Sarah Brightman sing All I Ask of You from The Phantom of the Opera starting at 0:39. This is a very disjunct melody, and challenging to sing. Great melodies also incorporate patterns that blend unity, repetition, and contrast. Our ears love patterns, but they also love novelty and growth. A good melody incorporates all of these elements. For example, listen to John Williamâs âPrincess Leia Theme.â Can you hear the repeated pattern in the melody that gradually moves higher as the theme progresses? Now listen to the way it changes and develops into something that fits with what came before but sounds new at the same time. This is some great melodic writing! Can melody exist without rhythm? There is no way for a melody to exist without rhythm. Even if your melody only has one note, that note has a duration, and thatâs the rhythm. If your melody has two notes, how long those notes last and how much time passes between hearing them is also a rhythm. A melody in music can often be recognized even when itâs performed with different rhythms. This frequently happens in live performances of pop, rock, and jazz, in which singers typically improvise slight rhythmic differences with each performance. No two renditions are exactly the same, and this constant reinterpretation keeps the music fresh. How to make a melody for a song on piano Creating your own melodies on the piano is easy and fun! There are so many ways you can discover a melody all your own. Here are a few ideas. Get some inspiration from the world around you. What can you hear right now? A clock ticking? A bird song? A car passing by your house? See if you can find some notes on the piano that imitate the sounds you hear. Think of a feeling youâd like to put into a melody. What are some ways you could make a string of notes sound happy, sad, angry, or maybe just thoughtful. Choose a line from a poem you like, or write your own. Read it out loud and put some feeling into it. Did your voice rise and fall in pitch as you were reading? Now go to the piano, start on any note you like, and try to imitate what happened when you read. Go up when your voice naturally went up, go down when your voice naturally went down. How did that sound? Now you have the perfect melody to go with those words. Too many keys on the piano? The truth is, most melodies use only a limited number of different notes. Try creating a melody using only the black keys. These form whatâs called a pentatonic scale. Itâs used in a lot of folk music traditions around the world and can be a great place to start if you want to create your own melodies. Remember, when you create your melody, keep it simple. Use repeated notes and steps, but add a few skips to keep things interesting. One tip about leaps: when you do put in a big leap, try doubling back and filling in the empty space you leaped over. This keeps the melody self-contained and easier to sing. Also, see if you can use the same patterns of notes and rhythms to give the melody unity, but also change those patterns to give it variety. There is no right or wrong way to create your own music. Keep trying combinations of notes and rhythms until you find something that you like. How many bars and notes are in a melody? Many types of music tend to have a prescribed number of bars, or measures. This will vary widely between different genres, and creates an overall sense of musical structure. If youâre writing a pop song, a verse will usually have between eight and sixteen bars. The prechorus that follows often has just four bars, and this âforeshorteningâ creates a sense of acceleration, driving the listener toward the chorus. The number of notes can also vary widely. A melody in music needs at least two notes, and a long and complex one can have hundreds or even thousands of notes. What is a countermelody in music? How many melodies should a song have? A counter melody is a melodic line that interacts with the primary melody as an independent but supportive voice. A great example of this is the song âWe Donât Talk about Bruno.â Each character sings their own melody during the piece, but these melodies all combine at the end as countermelodies. This produces a musical texture known as counterpoint. The same thing happens in âOne Day Moreâ from Les Miserables. The different melodies are first sung separately, but end up being combined in a splendid, complex texture that leads the music to its thrilling conclusion. The difference between a countermelody and regular harmony is that harmony usually supports the rhythms of the melody. A countermelody will move more independently, with different rhythms from those of the melody, and will often sound âmelodicâ when sung or played all by itself. A melodic song should have one main melody. This is the part that the lead voice sings. Itâs usually in the spotlight, and will be the most memorable part of the music. Anything else is either harmony, countermelody, or accompaniment. Does all music have to have a melody? A piece of music doesnât have to have a melody. There are many different kinds of music without melody. For example, a lot of music played on percussion instruments wonât have a melody. Listen to this example of Tahitian drumming. This is some great music, exciting and fun to listen to, but youâd have a hard time humming it. Itâs music, but it doesnât have a melody. Rap music is another style of music where there doesnât have to be a melody. In rap, words are chanted rather than sung. The performer will raise and lower the pitch of their voice for emphasis, but itâs the rhythm of the words that creates most of the music. Music can even lack any melody, at least in some sections. Listen to the opening chords of âDuel of the Fates.â This choral passage is all about harmony, with little rhythmic variance or sense of melody. But it makes an effective contrast with the next section, which is bustling with rapid instrumental melodies. In some pieces, there are multiple melodic lines but there is no one main melody. When music is made up of equally important countermelodies, it creates a contrapuntal texture. Baroque composer J.S. Bach was one of the greatest masters of this style, such as in his Little Fugue in G minor. It starts with a single melodic line, the subject, but then a countermelody is added, and then more and more until several melodic lines are playing together. Itâs fun to listen to, but once all the countermelodies are playing together it becomes hard to decide which part to hum along with! Youâll also hear a lot of counterpoint in jazz music, in which the different instruments are all playing together and improvising their own melodies that combine to create a rich, thick musical texture. Experience the wonder of melody in music! Whether youâre humming your favorite tune, or creating a new song all your own, melody is a memorable, shareable part of music. Enrich your music experience by being aware of, listening for, and enjoying the melodies all around you.
Name: Marco Ramirez - âI Am Not Batmanâ TW: language Itâs the middle of the night. And the sky is glowing like mad radioactive red. And if you squint, you could maybe see the moon through a thick layer of cigarette smoke and airplane exhaust that covers the entire city like mosquito net that wonât let the angels in. And if you look up high enough you could see me-standing on the edge of a eighty seven story building. And up there-a place for gargoyles and broken clock towers that have stayed still and dead for maybe like a hundred years-up there is me. And Iâm freakin Batman. And I gots Bat-mobiles and Bat-a-rangs and freakin Bat-caves like for real, and all it takes is a broom closet or a back room or a fire escape and Dannyâs hand-me-down jeans are gone. And my navy blue polo shirt? â The one that looks kinda good on me but has a hole on it near the butt from when it got snagged on the chain linked fence behind Arturoâs but it isnât even a big deal cause I tuck that part in and its like all good? âthat blue polo shirt? â Itâs gone too. And I get like, like transformational. And nobody pulls out a belt and whips Batman for talking back â-Or for not talking back âAnd nobody calls Batman simple â- Or stupid â- Or skinny â- And nobody fires Batmanâs brother from the Eastern Taxi Company âcause they was making cutbacks, neither, âcause they got nothing but respect, and not like afraid-respect. Just like respect-respect. âCause nobodyâs afraid of you. Cause Batman doesnât mean nobody harm. Ever. Cause all Batman really wants to do is save people and maybe pay Abuelaâs bills one day and die happy and maybe get like mad famous. For real.âŚAnd kill the Joker. Tonight, like most nights, Iâm all alone. And Iâm watchingâŚAnd Iâm waiting⌠Like a eagle. Or like a âno, yea, like a eagle. And my cape is flappinâ in the wind (âcause itâs freakinâ long), and my pointy ears are on, and that mask that covers like half my face is on too, and I got like bulletproof stuff all in my chest so no one could hurt me and nobody â nobody â is gonna come between Batman, And Justice. From where I am I could hear everything. Somewhere in the city thereâs a old lady picking Styrofoam leftovers up outta a trash can and sheâs putting a piece of sesame chicken someone spit out into her own mouth. And somewhere thereâs a doctor with a whack haircut in a black lab coat trying to find a cure for the diseases that are gonna make us all extinct for real one day. And somewhere thereâs a man, a man in a janitorâs uniform, stumbling home drunk and dizzy after spending half his paycheck on forty-ounce bottles of twist-off beer and the other half on a four hour visit to some ladyâs house on a street where the lights have all been shot out by people whoâd rather do what they do, in this city, in the dark. And half a block away from JanitorMan thereâs a group of good-for-nothings who donât know no better waiting to beat JanitorMan with rusted bicycle chains and imitation Lousiville Sluggers, and if they donât find a cent on him â which they wonât â theyâll just pound at him till the muscles in their arms start burning, till thereâs no more teeth to crack out. But they donât count on me. They donât count on no dark night (with a stomach full of grocery store brand macaroni-and-cheese and cut up Vienna sausages), Cause theyâd rather believe I donât exist, And from eighty-seven stories up I could hear one of the good-for-nothings say âGimmethecashâ real fast (like that) just âGimmethefuckingcashâ and I see JAnitorMan mumble something in drunk language and turn pale and from eighty-seven stories up I could hear his stomach trying to hurl its way out of his Dickies. So I swoop down like and fast and Iâm like darkness. Iâm like SWOOSH â- And I throw a Bat-a-rang at the one naked lightbulb â- And theyâre all like âwhoa-motherfucker-who-just-turned-out-the-lights?â ââWhatâs that over there?â â-âWhat?â â- âGimme whatchou got old manâ â- âDid anybody hear that?!â â- âNo, reallyâ â- âThere ainât. No. Bat.â â But then â- One out of three good-for-nothings gets it to the head! And number Two swings blindly into the dark cape before him but before his fist hits anything I grab a trash can lid and â-- Right into the gut, and number One comes back with a jump-kick but I know judo-karate too so Iâm like â-- Twice â-- but before I can do any more damage suddenly we all hear a CLIC â CLIC âAnd suddenly everything gets quiet And the one good-for-nothing left standing grips a handgun and aims straight up, like heâs holding Jesus hostage, like heâs threatening maybe to blow a hole in the moon. And the good-for-nothing who got it to the head who tried to jump-kick me and the other good-for-nothing who got it in the gut is both scrambling back away from the dark figure before him. And the drunk man the JanitorMan is huddled in a corner, praying to Saint Anthony âcause thatâs the only one he could remember. And thereâs me, Eyes glowing white, cape blowing softly in the wind. Bulletporoof chest heaving. My heart beating right through it in a Morse code for âfuck with me, just once, come on, just try.â And the one good-for-nothing left standing, the one with the handgun, he laughs he lowers his arm, and he points it at me and gives the moon a break, and he aims it right between my pointy ears, like goalposts and heâs special teams. And JanitorMan is still calling Saint Anthony but he ainât pickinâ up, And for a second it seems likeâŚmaybe Iâm gonna lose. Naw. SHOO â SHOO! FUACATA! --âDonât kill me man!â ââSNAP! â Wrist CRACK â Neck â SLASH! â Skin â meets â acid â âAHH!!â âAnd heâs on the floor. And Iâm standing over him. And I got the gun in MY hands now. And I hate guns, I hate holding âem cause Iâm Batman, and âBatman donât like guns âcause his parents got iced by guns a long time ago â but for just a second, my eyes glow white, and I hold this thing, for I could speak to the good-for-nothing in a language he maybe understandsâŚCLIC â CLICâŚAnd the good-for-nothings become good-for-disappearing into whatever toxic-waste-chemical-sludge-shit-hole they crawled out of. And itâs just me and JanitorMan. And I pick him up. And I wipe sweat and cheap perfume off his forehead. And he begs me not to hurt him and I grab him tight by his JanitorMan shirt collar and I pull him to my face, and heâs taller than me, but the cape helps so he listens when I look him straight in the eyes and I say two words to him: âGo home.â And he does, checking behind his shoulder every ten feet. And I SWOOSH from building to building on his way there, âcause I know where he lives. And I watch his hands where he lives. And I watch his hands tremble as he pulls out his keychain and opens the door to his building. And Iâm back in bed before he even walks in through the front door. And I hear him turn on the faucet and pour himself a glass of warm tap water And he puts the glass back in the sink. And I hear his footsteps, And they get slower as they get to my room. And he creaks my door open like mad slow. And he takes a step in, which he never does. And heâs staring off into nowhere, his face the color of sidewalks in summer, and I act like Iâm just waking up, and I say, âWhatâs up, Pop?â And JanitorMan says nothing to me. But I see, in the dark, I see his arms go limp and his head turns back, like towards me, and he lifts it for I could see his face, For I could see his eyes, And his cheeks is dripping but not with sweat. And he just stands there, breathing, like he remembers my eyes glowing white. Like he remembers my bulletproof chest. Like he remembers heâs my pop. And for a long time I donât say nothing. And he turns around, hand on the doorknob, and he ainât looking up my way but I hear him mumble two words to me. âIâm sorry.â And I lean over and open my window just a crack.⌠If you look up high enough you could see me. And from where I am? I could hear everything.
Lesson 25.Slow and fast (2)
Lesson 25.Slow and fast.