What is the purpose of the CPU?

Fetch, decode and execute instructions

Convert assembly language to binary

Translate high-level code into machine code

A computer is described as having two CPU cores and a clock speed of 2GHz. Which of these is true?

It can execute at most 4 billion instructions per second

It has two main memory stores, one for each core

It can execute at most 2 billion instructions per second

It has two separate sets of buses

After getting an instruction from main memory, the fetch stage increments the program counter so that it now holds what?

The address of the next instruction in the program

The address of the data required by the instruction

The contents of the Current Instruction Register (CIR)

In the fetch stage, where does the CPU fetch instructions from?

Secondary storage (e.g. HDD or SSD)

Which of these is not part of the instruction cycle?

copy an instruction from secondary storage to main memory

determine what instruction needs to be carried out

carry out the instruction, which could be an arithmetic or logic operation

retrieve an instruction from memory and increment the program counter

The Purpose of the CPU: Systems Architecture: Computer Science: GCSE (9:1)

Common On-Chip Peripherals: Serial Communication Interfaces: UART (Universal Asynchronous Receiver/Transmitter): Enables serial communication for data transmission and reception. SPI (Serial Peripheral Interface): Facilitates fast, synchronous serial communication with external devices. I2C (Inter-Integrated Circuit): Another common protocol for serial communication, often used for connecting sensors and other peripherals. Timers and Counters: General Purpose Timers: Used for generating precise time delays and measuring intervals. Real-Time Clock (RTC): Keeps track of time even when the DSP is in a low-power state. Watchdog Timer: Monitors the DSP's operation and resets it if it detects a fault. Interrupt Controllers: Interrupts: Allow peripherals to signal the DSP when an event occurs, enabling efficient and responsive system operation. Memory Management: DMA (Direct Memory Access): Enables data transfer between memory and peripherals without CPU intervention, improving efficiency. On-Chip Memory: Includes RAM, ROM, and flash memory for storing data and code. Audio/Video Interfaces: DAC (Digital-to-Analog Converter): Converts digital signals to analog signals for audio output. ADC (Analog-to-Digital Converter): Converts analog signals to digital signals for processing. I/O Ports: GPIO (General Purpose Input/Output): Provides flexible control over external devices. Ethernet MAC (Media Access Controller): Enables network connectivity. Other Peripherals: LCD Controller: For displaying information on LCD screens. USB Interface: For connecting to USB devices. CAN (Controller Area Network): For communication in automotive and industrial applications.

The purpose of the CPU - The fetch-execute cycle

In this video we take a look at the 0:02 fetch to code 0:03 execute cycle including its effect on 0:06 the various registers we've previously 0:12 [Music] 0:14 discussed a computer is defined Definition 0:17 as an electronic device that takes an 0:20 input 0:22 processes data 0:25 and delivers output 0:29 in this simple example you can see we're 0:31 taking the input 5 0:35 we're multiplying it by 2 that's our 0:37 process 0:39 and we're outputting 10. 0:44 but this could be way more complex for 0:46 example of a game console 0:48 the input could be the buttons you press 0:50 on a controller 0:53 the processes would then be carried out 0:55 by the console itself 0:59 and the output would be some form of 1:01 update to a monitor 1:02 and sound out for a speaker possibly 1:04 vibration feedback through the 1:06 controller 1:10 to process data a computer follows a set 1:13 of instructions 1:14 known as a computer program 1:18 if we take the lid off a typical desktop 1:20 computer we can identify 1:22 two critical components the memory 1:26 that stores the program and the central 1:29 processing unit or processor 1:31 which is under this large fan and 1:33 carries out the instructions 1:37 a computer carries out its function by 1:40 fetching 1:41 instructions decoding them and then 1:43 executing them 1:44 in a continuous repetitive cycle 1:46 billions of times a second 1:48 let's look at each of these stages in a 1:50 little more detail Fetch 1:53 so let's start with the fetch stage the 1:55 very first thing that happens 1:57 is the program counter is checked as it 2:00 holds the address 2:01 of the next instruction to be executed 2:07 the address stored is then copied into 2:09 the memory address register 2:14 the address is then sent along the 2:16 address bus to main memory 2:18 where it waits to receive a signal from 2:21 the control 2:22 bus so it knows what to do 2:27 as we want to read the data that's 2:29 stored in memory address 2:30 0 0 0 0 the control unit sends 2:34 a read signal along the control bus to 2:36 main memory 2:41 now main memory knows the data needs to 2:44 be read 2:45 the content stored in memory address 000 2:49 can be sent along the data bus to the 2:51 memory data register 2:56 now as we're currently in the process of 2:58 fetching an instruction 3:00 the data received by the memory data 3:03 register gets copied 3:04 into the current instruction register 3:11 the instruction effectively has now been 3:14 fetched from memory 3:16 just before we proceed to the decode 3:18 phase we now 3:19 increment the program counter so that 3:22 the address it contains 3:24 points to the address of the next 3:26 instruction which will need to be 3:30 executed 3:32 the instruction now being held in the 3:33 current instruction register 3:35 is ready to be decoded 3:39 now as we mentioned in the previous 3:41 video the instruction is made up of two 3:43 parts 3:44 we have the op code that's what it is we 3:47 need to do 3:50 and we have the operand what are we 3:53 going to do it to 3:55 now the operand could contain the actual 3:57 data 3:58 or indeed it could contain an address of 4:01 where the data is to be found 4:06 by decoding this instruction we can see 4:08 the operation we need 4:10 is a load operation so we need to load 4:14 the contents of memory location0101 4:18 into the cpus accumulator 4:25 in the exam a simple model will be used 4:27 to describe the 4:29 structure of any given instruction 4:32 you're not going to be expected to 4:34 define how an opcode is made up 4:36 but simply to interpret opcodes in the 4:39 given context of an exam 4:40 question in the example here 4:44 you can see there's a total of 16 4:46 different opcodes available 4:48 and this is because we're using four 4:50 bits for our representation 4:56 so now we've fetched the instruction and 4:59 we've decoded it so we know what we need 5:00 to do 5:01 we're finally ready to execute it 5:05 so we now send address 0101 5:08 to the memory dress register 5:13 now we're in the memory address register 5:15 we can finally send the address 5:18 down the address bus to main memory 5:24 this time we want to read the data 5:26 that's stored in memory 5:28 and so the control unit again sends a 5:30 read signal along the control bus 5:36 so main memories now receive an address 5:38 and a read signal 5:40 so the content stored at memory location 5:43 0101 5:44 can now be sent along the data bus back 5:46 to the cpu 5:47 and into the memory data register 5:54 finally the contents of the memory data 5:56 register are copied to the accumulator 5:59 and this is one of a number of general 6:00 purpose registers found in the cpu 6:04 this first instruction is now complete Branching 6:11 so what does this program actually do 6:14 you should be able to work it through 6:16 carefully and figure it out 6:19 we're now pointing instructions zero 6:21 zero zero one in the program counter 6:23 and we're ready to fetch the second 6:25 instruction 6:27 at the end of this video we're gonna 6:29 provide you with the answer 6:34 so let's talk a second about programs 6:37 that branch 6:40 on the left here we have a very simple 6:42 piece of pseudo code 6:44 line zero says first execute this line 6:46 of code 6:47 line 1 now execute this line and then 6:50 line 2 says 6:52 if the age is greater than 18 then 6:56 we're going to execute lines 3 and 4 6:58 otherwise 6:59 we're going to execute lines six and 7:02 seven 7:03 so this program doesn't necessarily 7:05 follow strictly in sequence from line 7:07 zero through to seven there's a chance 7:10 here the program may branch and jump 7:14 around 7:16 so we're going to pretend that this 7:17 program has been loaded into memory 7:20 each line of code on the left here has 7:23 ended up 7:24 as a location in memory now this is not 7:27 strictly how this would happen in this 7:28 one-to-one way 7:29 but for the purpose of example it's 7:31 absolutely fine 7:35 so the program counter starts by 7:37 pointing to memory address zero 7:39 and we fetch the first instruction 7:41 decode it and execute it 7:44 it then updates and tells us the next 7:47 instruction 7:48 is zero zero zero one because remember 7:50 the program counter is being incremented 7:52 so we fetch it decode it and we execute 7:55 line one of our program 7:59 we then fetch line two which in binary 8:01 is one 8:02 zero 8:06 now at this point depending on what 8:10 happens during the execution 8:11 of line two the program may be required 8:15 to fetch line three from memory or 8:18 line five from memory 8:25 so let's look at how this actually works 8:27 because we've said the program counter 8:28 simply gets incremented 8:31 well in the current instruction register 8:33 we have an instruction with the op code 8:36 0 1 1 0. 8:41 now when we look this up in the decode 8:43 unit we discover that this 8:45 code means branch always 8:51 this replaces the value held in the 8:54 program counter 8:56 with the contents of the operand that's 8:58 the second part of the instruction 9:01 from the current instruction register so 9:03 this case 9:04 one zero zero one 9:09 now when the next fetch cycle begins the 9:12 program counter is obviously checked 9:14 and as its contents have been previously 9:16 updated to a new memory location 9:19 and not simply incremented the program 9:22 effectively is able to jump 9:24 around memory 9:28 so having watched this video you should 9:30 be able to answer the following key 9:32 question 9:33 how does a cpu work 9:39 okay so let's um answer the question we 9:41 posed 9:42 earlier what did that program actually 9:48 do 9:50 so this is the first fetch to code 9:53 execute cycle 9:55 and this is the one that we ran through 9:57 in detail earlier 9:58 it effectively loaded the contents of 10:01 the memory 10:02 stored at location location0101 10:05 into the accumulator in other words 10:08 the dna number 3 is moved 10:11 from memory into the cpu 10:18 we then proceed onto the second fetch 10:20 decode execute cycle 10:23 now this one adds the contents of memory 10:27 located at 0 1 1 0 10:30 to the current contents of the 10:32 accumulator 10:34 so in other words the dna number one 10:38 because that's what's stored at address 10:40 zero one one zero 10:43 is added to the number three that was in 10:45 the accumulator 10:46 the results are stored back over the 10:48 accumulator 10:49 so effectively we've done three plus one 10:53 equals four 10:58 the third fetch to code execute cycle 11:00 stores the contents which are in the 11:02 accumulator 11:03 into memory location zero one one one 11:07 and that's because the op code the first 11:09 part of this current instruction 11:10 zero zero one one is the command to 11:13 store when we look it up in the decoder 11:15 unit 11:16 so in other words the result of the 11:17 previous calculation three plus one 11:19 equals four 11:20 is now written back into main memory 11:28 the fourth fetch decode execute cycle 11:30 outputs the contents of the accumulator 11:33 remember they were copied into main 11:34 memory but they're still held in the 11:35 accumulator 11:37 so in this simple abstraction the number 11:40 four is now 11:41 output to the user so they can see the 11:43 result of the calculation 11:49 the fifth and final fetch code execute 11:51 cycle 11:52 brings a halt to the current program 11:58 so this very simple program which has 12:01 five 12:02 fetch decode execute cycles has 12:04 performed the calculation 12:06 three plus one is then stored the result 12:09 in main memory 12:10 and displayed the result four to the 12:12 user 12:13 and in a high-level language this may 12:15 look something very similar to the 12:17 following two lines of code 12:20 sum variable equals num1 plus num2 12:24 print sum to the user 12:27 so you can start to get an appreciation 12:29 here of how the high level code you 12:32 write actually ends up being fetched 12:34 decoded 12:35 and executed inside a processor 12:38 of course your processor is doing 12:40 billions and billions of these 12:42 operations a second 12:43 which when you think about it is really 12:45 very impressive 12:52 [Music] 13:03 you. make 10 questions for a standerd of a level

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Question 1: What is the primary purpose of using rubrics in assessment? A. To reduce the number of assignments teachers must grade B. To give students random feedback C. To assess learner performance using specific criteria and levels D. To make grading faster and easier for instructors Question 2: Which of the following is a characteristic of analytic rubrics? A. Assess the entire task as a whole B. Provide a single descriptive paragraph for all criteria C. Use multiple criteria with individual performance descriptors D. Do not include any scoring scale Question 3: What is one benefit of using rubrics in education? A. They eliminate the need for grading B. They confuse learners about expectations C. They help provide informative and constructive feedback D. They discourage students from revising their work Question 4: When choosing between an analytic and a holistic rubric, which is true? A. Holistic rubrics provide detailed feedback for each component B. Analytic rubrics assess the task as a whole C. Holistic rubrics are used to give a general judgment of overall performance D. Analytic rubrics are used when no feedback is needed Question 5: Which of the following is not a step in developing a rubric? A. Define the purpose of the learning task B. Choose rubric type C. Design final exam questions D. Write performance descriptors Question 6 What does “content validity” refer to in assessment instruments? A. The extent to which the test predicts future performance B. The extent to which test items cover the intended content C. How consistent the results of the test are over time D. The judgment of whether a test looks valid on the surface Question 7 Which type of reliability involves the consistency of scores given by two or more raters? A. Intra-rater reliability B. Test-retest reliability C. Inter-rater reliability D. Internal consistency Question 8 Which statistical method is used to confirm that all items measure the intended construct? A. Content mapping B. Guessing analysis C. Construct charting D. Confirmatory Factor Analysis (CFA) Question 9 According to the PDF, what is one way to increase the validity of an assessment instrument? A. Shorten the test to reduce variability B. Apply penalties for guessing C. Conduct a vetting session with experts D. Use the same rater for all responses Question 10 In the affective domain construct map, what is the highest level of affective behavior? A. Responding B. Valuing C. Characterisation D. Organisation

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