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The Revealers Chapters 6-17
Quiz by Katie Scott
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SPANISH STUDENTS 10/22/25 In the sentence 'The author chose to juxtapose the wealthy neighborhood with the impoverished area to highlight social inequality,' what does 'juxtapose' most likely mean based on context clues? * 1 point to separate completely to describe in detail to criticize harshly to place side by side for comparison When reading 'This paradox confused everyone: the more he tried to save time, the less time he seemed to have,' what can you infer about a paradox? * 1 point a mathematical equation a simple solution a type of poem a contradictory statement that reveals truth The passage states: 'The author's use of symbolism was evident when the broken mirror represented the character's shattered dreams.' Based on this context, symbolism involves: * 1 point using objects to represent deeper meanings creating rhyming patterns writing in chronological order using literal descriptions only In the text 'Please elaborate on your answer by providing specific examples and detailed explanations,' the word 'elaborate' suggests the need to: * 1 point use simpler words change the topic add more detail make it shorter The critic wrote: 'The actor's performance captured every nuance of emotion, from subtle sadness to barely contained rage.' What does 'nuance' refer to in this context? * 1 point subtle variations in meaning simple emotions loud expressions obvious differences When the text says 'The implication of her silence was clear to everyone in the room, though she never spoke a word,' what does 'implication' mean? * 1 point a command given a direct statement a question asked a conclusion drawn indirectly The scientist stated: 'Based on our limited observations, our hypothesis suggests that plants grow faster with classical music.' What is a hypothesis? * 1 point a type of experiment a proven fact a final conclusion a possible explanation needing more evidence In 'Three witnesses were able to corroborate the defendant's alibi, strengthening his case significantly,' the word 'corroborate' most likely means: * 1 point to question or doubt to confirm or support to change the story to ignore completely The passage reads: 'The student needed to justify her controversial thesis with solid evidence and logical reasoning.' What does 'justify' mean here? * 1 point to make it longer to make excuses for to avoid explaining to prove something is reasonable When the text states 'The researcher was able to synthesize information from five different studies to create a comprehensive theory,' what does 'synthesize' involve? * 1 point copying one source exactly combining multiple sources to create something new rejecting all previous research focusing on only one idea When a reader encounters 'The symbolism in the novel was complex, with the recurring image of doors representing new opportunities throughout the story,' they should: * 1 point memorize all symbols skip symbolic passages look for deeper representational meanings focus only on the literal meaning If a teacher says 'Your essay needs more elaboration - expand on your main points with examples and analysis,' what critical thinking skill is being requested? * 1 point developing ideas with supporting details summarizing briefly using fewer examples changing the topic entirely In the passage 'The dark clouds gathering on the horizon seemed to foreshadow the troubles that would soon befall the village,' what literary technique is being demonstrated? * 1 point The author is using environmental details to hint at future plot developments The author is focusing on realistic weather descriptions The author is using weather to predict actual meteorological events The author is describing a coincidental weather pattern When analyzing 'Sarah knew the antagonist in her favorite novel wasn't just evilâhe represented the fear of change that many people experience,' what deeper understanding about antagonists is revealed? * 1 point Antagonists are always completely evil characters Antagonists can represent abstract concepts or human struggles Antagonists must be human characters Antagonists only exist to create action scenes In the sentence 'The protagonist's journey wasn't just about reaching the destinationâit was about discovering who she truly was,' what does this suggest about effective protagonists? * 1 point Protagonists must always succeed in their missions Protagonists should remain unchanged throughout the story Protagonists undergo both external and internal development Protagonists should focus only on external goals When the text states 'The word 'home' carried different connotations for each characterâwarmth and safety for some, confinement and obligation for others,' what critical reading skill is being highlighted? * 1 point Memorizing dictionary definitions Understanding that words have only one correct meaning Identifying grammatical structures Recognizing that word meanings can vary based on personal experience In 'While the denotation of 'snake' is simply a reptile, the author's use of it to describe the character suggests something far more sinister,' what analytical skill is required? * 1 point Understanding reptile biology Memorizing animal classifications Distinguishing between literal and figurative meanings Identifying sentence structure When examining 'The author's tone shifted from hopeful in the opening chapters to increasingly cynical as the story progressed,' what does this reveal about sophisticated writing? * 1 point Tone is unimportant in storytelling Tone changes reflect the author's developing attitude toward the subject Only the ending tone matters Authors should maintain the same tone throughout In analyzing 'The theme of the novel wasn't stated directly but emerged through the characters' repeated struggles with moral choices,' what does this demonstrate about themes? * 1 point Themes develop through patterns in the narrative Themes are only found in the conclusion Themes should always be explicitly stated Themes must be simple moral lessons When the passage reads 'From the character's nervous glances and hesitant speech, readers can infer that she's hiding something important,' what critical thinking process is being described? * 1 point Following explicit plot statements Memorizing character descriptions Making random guesses about character motivations Using textual evidence to draw logical conclusions In 'The ending was deliberately ambiguous, allowing readers to decide whether the character's actions were heroic or selfish,' what does this suggest about sophisticated literature? * 1 point Good stories always have clear, definitive endings Unclear endings indicate poor writing Ambiguity can enhance reader engagement and interpretation Authors should avoid confusing readers When analyzing 'The controversial decision to ban the book sparked debates about censorship versus protecting young readers,' what critical thinking skill is most important? * 1 point Choosing one side immediately Examining multiple perspectives before forming an opinion Avoiding difficult topics entirely Following popular opinion In 'Each character's perspective on the same event revealed how personal experiences shape our understanding of truth,' what deeper concept is being explored? * 1 point All perspectives are equally valid Perspective is unimportant in understanding events There is only one correct way to view any situation Personal background influences how we interpret events When the text states 'The community proved resilient, rebuilding not just their homes but their hope after the disaster,' what does this reveal about the concept of resilience? * 1 point Resilience encompasses both practical and emotional recovery Resilience is an innate trait that cannot be developed Resilience means avoiding all difficulties Resilience only involves physical recovery In analyzing 'The author's portrayal of the character's empathyâher ability to understand her enemy's pain even while fighting himâadded complexity to the conflict,' what does this suggest about empathy? * 1 point Empathy means agreeing with everyone Empathy makes people weak in conflicts Empathy should be avoided in difficult situations Empathy can coexist with opposition and create moral complexity When examining 'The character's integrity was tested when telling the truth would hurt people she loved,' what does this reveal about integrity? * 1 point Integrity means always following rules regardless of consequences Integrity means never causing any harm to others Integrity is only important in public situations Integrity involves making difficult moral choices even when costly In 'The student learned to advocate for her ideas by presenting evidence rather than just stating opinions,' what critical skill is being developed? * 1 point Supporting positions with logical reasoning and evidence Avoiding controversial topics entirely Learning to argue loudly and persistently Always agreeing with authority figures If you rewrote a scene from 'The Birchbark House' from Omakayas's grandmother's first-person perspective instead of Omakayas's, how would this most likely change the reader's understanding? * 1 point Nothing would change since they're both female characters The language would become more formal and difficult The story would become less interesting because adults are boring Readers would gain wisdom from experience but lose the innocence of childhood discovery In a plot diagram, the rising action serves which critical purpose beyond simply building toward the climax? * 1 point To provide background information about the setting To confuse readers so the ending is surprising To develop character relationships and establish stakes that make the climax meaningful To make the story longer and more detailed When analyzing the falling action in 'The Birchbark House,' which element would be most important to consider when writing an alternate version? * 1 point Whether the consequences of the climax align with the new direction you want the story to take Making sure it's shorter than the rising action Including a moral lesson for readers How quickly the conflicts get resolved In the exposition of a story, conflict serves which essential function that many readers don't realize? * 1 point To immediately grab attention with action scenes To provide comic relief before serious events To show off the author's writing skills To establish what the characters characterization/personality, which determines what they' must learn to overcome as they face more problems
Alexa and Brittany were best friends. Theyâd known each other since Brittany moved next door in 2nd grade. They hung out almost every day after school⌠when they were getting along, that is. They were very different people. Alexa did great with her school work, read a lot of books, and took ballet classes. Brittany, on the other hand, would rather play soccer, chat with other kids at school, and rarely sat still for long enough to finish reading a chapter of a book. Often, Alexa and Brittany would play together at the park across the street. Theyâd play on the equipment, play tag with a group of neighborhood kids, or play soccer. If it was raining outside, theyâd go in one of their houses to make crafts, play video games, or do their nails. Some days they could spend hours together without a single problem, but other days they just could not agree on what to do. âCome on, letâs play on the equipment. Weâve played soccer for the last three days!â Alexa said. âThey just cut the grass, I love playing soccer when the grass is nice and short. I donât want to play on the equipment,â Brittany replied. âWe always do what you want to do Brittany, itâs my turn to choose.â Alexa was getting frustrated. âFine, go play on the equipment by yourself, Iâm playing soccer, â Brittany shouted. Grade 5 Reading Comprehension Worksheet Reading and Math for K-5 Š www.k5learning.com Alexa left. She was fuming. When she got home, she realized she still had Brittanyâs notebook. Well, Iâm not giving it back today. Iâm too mad at her. Alexa thought. The next day at school, their teacher asked for their notebooks. Brittany didnât have hers, and asked Mrs. Stone if she could bring it in tomorrow instead. Mrs. Stone let us have one late assignment a month, but Brittany had already used hers. Brittany looked upset, and walked quietly back to her desk. Alexa was having an internal conflict. She knew she should tell Mrs. Stone that she had the notebook, but she was still mad at Brittany for not compromising with her at the park yesterday. When it was time for lunch, Alexa hung back to talk with Mrs. Stone. âMrs. Stone, I have Brittanyâs notebook. I should have said something earlier, but Alexa and I had a problem yesterday, and Iâm still mad at her. Would you be able to help us solve our problem?â Alexa asked. âThank you for being honest, Alexa. Iâm sure Brittany will appreciate that you gave me her notebook when you could have made her get another late mark instead. Iâm glad you asked for help solving the problem. Itâs really hard to solve a problem by yourself when youâre still feeling upset, so this is a good solution.â At recess, Mrs. Stone sat and talked with the girls. They each revealed that they get frustrated with the other person a lot because they donât always want to do the same things, but they real ized that they never really solved their problem. One of them just always went home. Mrs. Stone helped them realize that maybe they didnât have to play together every day to be best friends. They decided to just play together a couple times a week, and take turns picking the activity. Alexa and Brittany were hopeful that this would solve a lot of the arguments theyâd been having lately!
The Pleiades, also known as the Seven Sisters, is a famous star cluster located in the constellation of Taurus. It is made up of a group of seven bright stars that are visible to the naked eye in the night sky. The stars in the Pleiades cluster are relatively young, being only about 100 million years old, which is young in astronomical terms. The Pleiades cluster has been observed and admired by cultures all around the world for thousands of years. In Greek mythology, the Pleiades were seven sisters who were pursued by the hunter Orion. To protect them, Zeus transformed them into stars, forming the star cluster we see today. Different cultures have their own stories and legends associated with the Pleiades, making it a fascinating object of study for astronomers and a source of inspiration for artists and storytellers. The Pleiades cluster is often used as a test of eyesight, as people are challenged to count how many stars they can see with the naked eye. Most people can see six or seven stars, but those with particularly sharp vision may be able to see more. The Pleiades is also a popular target for amateur astronomers with telescopes, as the cluster reveals even more stars and details when viewed through a telescope. In addition to being a beautiful sight in the night sky, the Pleiades cluster also serves a practical purpose for astronomers. By studying the stars in the Pleiades, scientists can learn more about how stars form and evolve, as well as gain insights into the structure and composition of the Milky Way galaxy. The Pleiades cluster continues to be an important object of study for astronomers, both amateur and professional, and its beauty and significance will continue to capture the imaginations of people for generations to come. Matariki is the Maori name for the Pleiades star cluster. The Pleiades is a group of stars that can be seen in the night sky, and Matariki is a special time of year when the star cluster is visible in the sky. In Maori culture, Matariki is seen as the beginning of the Maori New Year, and it is a time to celebrate and give thanks for the past year and look forward to the year ahead. So basically, Matariki is related to the Pleiades because it is a special time of year when those stars are visible in the sky and it has cultural significance for the Maori people. The Pleiades star cluster is known by different names in various cultures around the world. Here are some of the names by which the Pleiades are referred to in different countries: 1. Maori culture in New Zealand and Polynesia: Matariki 2. Greek mythology: The Seven Sisters 3. Japan: Subaru 4. Native American tribes: The Dancers or The Little Eyes 5. Inca civilization: Collca 6. Ancient Persia: Parvin 7. India: Krittika 8. Aboriginal Australians: The Seven Sisters or Djulpan These different names reflect the diverse cultural significance and interpretations of the Pleiades cluster in various societies throughout history.
consider deem to be At the moment, artemisinin-based therapies are considered the best treatment, but cost about $10 per dose - far too much for impoverished communities. Seattle Times (Feb 16, 2012) minute infinitely or immeasurably small The minute stain on the document was not visible to the naked eye. accord concurrence of opinion The committee worked in accord on the bill, and it eventually passed. evident clearly revealed to the mind or the senses or judgment That confidence was certainly evident in the way Smith handled the winning play with 14 seconds left on the clock. practice a customary way of operation or behavior He directed and acted in plays every season and became known for exploring Elizabethan theatre practices.
Slide 1: ⢠Title slide with the presentation topic: "Understanding Context in Film Analysis" Slide 2: ⢠Introduction to the importance of context in film analysis. ⢠Engaging visuals to capture students' attention. ⢠Emphasize that context provides a deeper understanding of a film's meaning. Slide 3: ⢠Definition of Context: ⢠Context refers to the surrounding circumstances or conditions that influence the creation, interpretation, and reception of a film. ⢠Analyzing context helps uncover layers of meaning, societal influences, and enhances critical thinking skills. Slide 4: ⢠Historical Context: ⢠Definition: Historical context refers to the specific time period in which a film was created and/or set. ⢠Importance: Understanding the historical context helps us connect the film to its time period and comprehend the influence of historical events, social norms, and cultural movements. ⢠Example: Analyzing the historical context of "Gone with the Wind" (1939) allows us to appreciate how the film reflects the post-Civil War era in the United States and addresses themes of race, class, and gender. Slide 5: ⢠Social Context: ⢠Definition: Social context refers to the social structures, norms, and values prevalent during the time of a film's creation and/or setting. ⢠Importance: Examining the social context helps us understand how societal attitudes and values shape the film's narrative, characters, and themes. ⢠Example: Analyzing the social context of "The Breakfast Club" (1985) reveals how the film explores the social dynamics and stereotypes within a high school setting, reflecting the cultural climate of the 1980s. Slide 6: ⢠Political Context: ⢠Definition: Political context refers to the political climate and ideologies present during the time of a film's creation and/or setting. ⢠Importance: Understanding the political context helps us uncover political messages, power dynamics, and social commentary within the film. ⢠Example: Examining the political context of "V for Vendetta" (2005) allows us to appreciate how the film critiques totalitarianism and explores themes of government control and individual freedom. Slide 7: ⢠Authorial/Directorial Context: ⢠Definition: Authorial/Directorial context refers to the background, artistic choices, and intentions of the director or filmmaker. ⢠Importance: Analyzing this context helps us understand the director's unique vision, influences, and storytelling techniques, which shape the film's style and thematic focus. ⢠Example: Exploring the authorial/directorial context of "Pulp Fiction" (1994) reveals Quentin Tarantino's nonlinear storytelling, pop culture references, and exploration of morality and violence. Slide 8: ⢠Importance of considering multiple contexts together: ⢠Analyzing multiple contexts together provides a comprehensive understanding of a film's meaning and impact. ⢠Exploring the interplay between historical, social, political, and authorial/directorial contexts deepens our insights and enhances critical analysis skills. Slide 9: ⢠Case studies: ⢠Present two different films as case studies. ⢠Example 1: Analyzing the historical context, social context, and authorial/directorial context of "Black Panther" (2018) provides insights into its exploration of Afrofuturism, cultural identity, and representation. ⢠Example 2: Examining the historical context, political context, and authorial/directorial context of "Citizen Kane" (1941) reveals its commentary on power, media, and the American dream. Slide 10: ⢠Summary slide: ⢠Recap the main points about context in film analysis. ⢠Encourage students to apply these concepts to their own analysis.
LESSON 4. Cellular Respiration ⢠Define cellular respiration ⢠Identify the stages of clan respiration You have just learned how the energy from the sun is captured, processed, and stored in the form of glucose. Cellular respiration, another important life process, is the means by which cells release the stored energy in glucose to make adenosine triphosphate (ATP). The primary goal of this life process is to convert stored energy into usable form, such as ATP, for the cells to carry out their functions. Cellular respiration involves several chemical reactions. The reactions can be summed up in the following equation: C6 H12 O6 + 602 -----ď 6 COâ +6HâO + ATP Glucose oxygen carbon dioxide water energy Aerobic respiration reactions, or cellular respiration that takes place in the presence of oxygen, can be grouped into three stages glycolysis, Krebs cycle, and electron transport chain (ETC). Stage 1: Glycolysis Glycolysis is the process that breaks down one molecule of 6-C glucose into 3-C pyruvates or pyruvic acids. It also releases four molecules of ATP. This process occurs in the cytoplasm of the cell. The following is the step-by-step process of glycolysis. Take note that several enzymes are involved in this process. 1. The first step of glycolysis requires energy. It can only proceed when the two ATP molecules donate energy to the glucose by transferring a phosphate group with the help of an enzyme, producing glucose 6-phosphate 2. Then, a specific enzyme promotes the rearrangement of the atoms, producing the fructose 6-phosphate. 3. The action of the enzyme in step 2 promotes the transfer of a phosphate group from another ATP molecule, forming fructose 1,6-bisphosphate. 4. The resulting fructose 1,6-bisphosphate molecules, with the help of another enzyme, splits into two molecules, each with three carbon backbones. These two sugars are dihydroxyacetone phosphate and glyceraldehyde 3-phosphate. 5. Another important enzyme then rapidly interconverts the molecules of dihydro-xyacetone phosphate and glyceraldehyde 3-phosphate. This produces two molecules of glyceraldehyde 3-phosphate or 3-phosphoglyceraldehyde (PGAL) 6. The succeeding step involves another enzyme-mediated action. The hydrogen (H) from PGAL is transferred to the oxidizing agent, nicotinamide adenine dinucleotide (NAD), which forms NADH. A phosphate (P) is also added from the cytosol of the cell to oxidize the two molecules of PGAL, forming two 1.3-bisphosphoglycerate. 7. A phosphate (P) from 1,3-biphosphoglycerate is transferred to ADP to form ATP. This happens for each of the two 1,3-bisphosphoglycerate. resulting to a yield of two ATP and two 3-phosphoglycerate molecules. 8. A phosphate is transferred from 3-phosphoglycerate molecules from the third carbon to the second carbon, forming 2-phosphoglycerate molecules A hydrogen atom and a hydroxyl ((OH) group is released, which then combines to form water (H2O). The removal of H2O from 2-phosphoglycerate results in the formation of 2- phosphoglycerate molecules. 9. A hydrogen atom and a hydroxyl ((OH) group is released, which then combines to form water (H2O). The removal of H2O from 2-phosphoglycerate results in the formation of two phosphoenolpyruvic acid (PEP) 10. Phosphate (P) from PEP is transferred to ADP (and forms ATP) and the final product, pyruvic acid. This reaction yields two molecules of pyruvic acid and two ATP molecules In summary, a single glucose molecule that undergoes the process of glycolysis produces two molecules of pyruvic acid, four molecules of ATP, two molecules of NADEL and two molecules of H.O. However, only two molecules of ATP are counted as net products since two molecules of ATP are spent throughout the process. Stage II: Krebs Cycle The Krebs cycle, named after its proponent Sir Hans Adolf Krebs, is a cyclical series of enzyme-controlled reactions. This stage of cellular respiration occurs in the matrix of the mitochondria. It is sometimes. called the citric acid cycle (CAC) since it produces citric acid. Citric acid contains three carboxyl (COOH) groups; hence, it is also called the tricarboxylic acid cycle (TCA). This requires the pyruvic acids produced during glycolysis. The main function of this cycle is to produce high-energy-yielding molecules, namely, NADH and flavin adenine dinucleotide (FADH) that will later on be used in the electron transport chain reaction. Figure 6-7. Summary of glycolysis and corresponding products in each reaction presented (See Appendix F on page 285 for an enlarged and complete version of the image.) An initial process is needed for the Krebs cycle to begin. As a pyruvate molecule from glycolysis enters the mitochondrion, it undergoes an important preliminary ate to form acetyl-CoA reaction. Coenzyme-A (COA) combines with pyruvate help of an enzymatic complex. This conversion also produces CO, and NADH. The Krebs cycle is summarized as follows. Take note that several enzymes are involved in this process. 1. The Krebs cycle technically begins when the acetyl-CoA combines with oxaloacetic acid (OAA), a 4-C molecule, to produce citric acid, a 6-C molecule. 2. With the aid of an enzyme, the citric acid now goes through a series of reactions that releases energy. Water molecule is removed from the citric acid and is returned in a different location. The-OH group is repositioned, forming the molecule isocitrate. 3. Isocitrate is then oxidized, forming the a-ketoglutarate, a 5-C molecule. The byproducts of this reaction are NADH and CO, 4 The a-ketoglutarate loses its CO, and a coenzyme-A is added in its place. The decarboxylation occurs with the help of NAD, which then becomes NADH. The resulting molecule is called succinyl-CoA. 5. Succinyl-CoA is converted into succinate. Also in this reaction, a molecule of guanosine triphosphate (GTP) is synthesized. The GTP molecule has similar structure and energy properties to that of ATP and is used by cells the same way. The free phosphate group attacks the succinyl-CoA molecule, which detaches the COA. Then, phosphate is attached to GDP to come up with GTP, similar to the process that occur in ATP synthesis (from ADP to ATP). 6. Two hydrogens are removed from succinate, A molecule of flavin adenine dinucleotide (FAD), a coenzyme similar to NAD, is reduced to FADH, as it takes the hydrogens from the succinate. This reaction produces the fumarate. 7. Fumarate is then converted into malate as the addition of a water molecule is catalyzed. The final reaction is the regeneration of oxaloacetate. The resulting byproduct of this regeneration is NADH Recall that two pyruvate molecules were produced during glycolysis, causing the Krebs cycle to turn twice. Each tuts produces three molecules of NADH, single ATH one FADIH, and the by-product CO, which is exhaled. Stage III: Electron Transport Chain The electron transport chain (ETC) is a series of photon pumps on the inner membrane of the mitochondrion. Electron transport is the last stage of the cellular respiration. In this stage, the energy from NADH and FADH, from the Krebs cycle is transferred to ADP to produce ATP. This process is generally known as oxidative phosphorylation. This energy coupling mechanism in the cell was revealed by the work of Peter stored energy in the form of proton (1) gradient to phosphorylate (add phosphate) ADP and produce ATP. The pumping of hydrogen sons across the inner membrane creates higher concentration ions in the inner membrane than on the outside of the membrane. This chemiosmotic gradient causes the ions to flow back across the membrane where the concentration of ions is lower. ATP synthase lined in the matrix serve as a channel protein, helping the ions to move across the membrane. The chemiosmotic gradient powers the phosphorylation of ADP to ATP, which also occurs in the ATP synthase. After passing through the ETC, the oxygen, being the final hydrogen acceptor, combines with two electrons and two protons, forming a water molecule. Water is a by-product of cellular respiration and is excreted. MINI TEST 6-3 1. Which energy-releasing pathway yields the most ATF in each glucose molecule? 2. Briefly describe the two stages of aerobic respiration that follow glycolysis: (a) Krebs cycle (b) Electron transport chain Anaerobic Respiration Most cells carry out arrobic respiration when oxygen is present. Aerobic respiration is an efficient process that yields a lot of ATP. However, many organisms thrive in mud, marshes, animal gut, canned goods, sewage treatment pond, and deep oceans where oxygen is scarce. Organisms that can live without oxygen are called anaerobes. Cellular respiration that proceeds without the presence of oxygen is called anaerobic respiration. In the event that the oxygen supply becomes low, aerobic cells also perform fermentation and lactic acid fermentation anaerobic pathways. There are two common anaerobic pathways in these cells, alcoholic fermentation and lactic acid fermentation. In alcoholic fermentation, ethyl alcohol and carbon dioxide are produced by some cells using the pyruvate from glycolysis. Each pyruvate molecule is rearranged into acetaldehyde and carbon dioxide, which is eventually released. NADII gives up electrons to acetaldehyde to form ethanol Fermentation is widely used in the industry. Yeast, a fungus used in making bread. can undergo anaerobic respiration. Bakers aux sugar, flour, water, and yeast to form the bread dough. The dough rises due to the carbon dioxide and alcohol released by the yeast cells trapped in air bubbles. Beer and wine manufacturers, we yeast to ferment the sugars in wheat and grape juice, forming alcoholic beverages such as beer and wine. In some cells, glycolysis produces two pyruvates, two NADH molecules, and two ATP molecules. Pyruvate itself becomes the final acceptor of the electrons from the NADH that produces the final product: lactate. Oftentimes, this product is called lactic acid. Human skeletal muscles can carry out fermentation when the blood cannot supply the cells with adequate oxygen during strenuous activities. When lactic acid builds up in the muscles, fatigue, burning sensation, and cramps result. Lactic acid will continue to build up until there is adequate supply of oxygen. Lactic acid is then converted back into pyruvate in the liver. Muscles also restore normal functions. Have you ever wondered why milk or cream turns sour after some time? Bacterial cells that undergo fermentation are responsible in producing lactate that turns the milk sour. These bacteria are used in manufacturing yogurt and sour milk products. Fermentation pathways do not breakdown and utilize the glucose completely. ATP is no longer produced beyond the process of glycolysis. Thus, energy produced is just enough for some single-celled organisms, or the energy can only be used by multicellular organisms for a short period.
Introduction to Free Fall A free-falling object is an object that is falling under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. There are two important motion characteristics that are true of free-falling objects: ⢠Free-falling objects do not encounter air resistance. ⢠All free-falling objects (on Earth) accelerate downwards at a rate of 9.8 m/s/s (often approximated as 10 m/s/s for back-of-the-envelope calculations) Because free-falling objects are accelerating downwards at a rate of 9.8 m/s/s, a ticker tape trace or dot diagram of its motion would depict an acceleration. The dot diagram at the right depicts the acceleration of a free-falling object. The position of the object at regular time intervals - say, every 0.1 second - is shown. The fact that the distance that the object travels every interval of time is increasing is a sure sign that the ball is speeding up as it falls downward. Recall from an earlier lesson, that if an object travels downward and speeds up, then its acceleration is downward. Free-fall acceleration is often witnessed in a physics classroom by means of an ever-popular strobe light demonstration. The room is darkened and a jug full of water is connected by a tube to a medicine dropper. The dropper drips water and the strobe illuminate the falling droplets at a regular rate - say once every 0.2 seconds. Instead of seeing a stream of water free-falling from the medicine dropper, several consecutive drops with increasing separation distance are seen. The pattern of drops resembles the dot diagram shown in the graphic at the right. The Acceleration of Gravity It was learned in the previous part of this lesson that a free-falling object is an object that is falling under the sole influence of gravity. A free-falling object has an acceleration of 9.8 m/s/s, downward (on Earth). This numerical value for the acceleration of a free-falling object is such an important value that it is given a special name. It is known as the acceleration of gravity - the acceleration for any object moving under the sole influence of gravity. A matter of fact, this quantity known as the acceleration of gravity is such an important quantity that physicists have a special symbol to denote it - the symbol g. The numerical value for the acceleration of gravity is most accurately known as 9.8 m/s2. There are slight variations in this numerical value (to the second decimal place) that are dependent primarily upon on altitude. We will occasionally use the approximated value of 10 m/s2 in order to reduce the complexity of the many mathematical tasks that we will perform with this number. By so doing, we will be able to better focus on the conceptual nature of physics without too much of a sacrifice in numerical accuracy. g = 9.8 m/s2, downward Look It Up! Even on the surface of the Earth, there are local variations in the value of the acceleration of gravity (g). These variations are due to latitude, altitude and the local geological structure of the region. Recall from an earlier lesson that acceleration is the rate at which an object changes its velocity. It is the ratio of velocity change to time between any two points in an object's path. To accelerate at 9.8 m/s2 means to change the velocity by 9.8 m/s each second. If the velocity and time for a free-falling object being dropped from a position of rest were tabulated, then one would note the following pattern. Time (s) Velocity (m/s) 0 0 1 - 9.8 2 - 19.6 3 - 29.4 4 - 39.2 5 - 49.0 . Observe that the velocity-time data above reveal that the object's velocity is changing by 9.8 m/s each consecutive second. That is, the free-falling object has an acceleration of approximately 9.8 m/s2. Another way to represent this acceleration of 9.8 m/s2 is to add numbers to our dot diagram that we saw earlier in this lesson. The velocity of the ball is seen to increase as depicted in the diagram at the right. (NOTE: The diagram is not drawn to scale - in two seconds, the object would drop considerably further than the distance from shoulder to toes.) Representing Free Fall by Graphs ⢠Early in Lesson 1 it was mentioned that there are a variety of means of describing the motion of objects. One such means of describing the motion of objects is through the use of graphs - position versus time and velocity vs. time graphs. In this part of Lesson 5, the motion of a free-falling motion will be represented using these two basic types of graphs. Representing Free Fall by Position-Time Graphs A position versus time graph for a free-falling object is shown below. Observe that the line on the graph curves. As learned earlier, a curved line on a position versus time graph signifies an accelerated motion. Since a free-falling object is undergoing an acceleration (g = 9.8 m/s/s), it would be expected that its position-time graph would be curved. A further look at the position-time graph reveals that the object starts with a small velocity (slow) and finishes with a large velocity (fast). Since the slope of any position vs. time graph is the velocity of the object (as learned in Lesson 3), the small initial slope indicates a small initial velocity and the large final slope indicates a large final velocity. Finally, the negative slope of the line indicates a negative (i.e., downward) velocity. Representing Free Fall by Velocity-Time Graphs A velocity versus time graph for a free-falling object is shown below. Observe that the line on the graph is a straight, diagonal line. As learned earlier, a diagonal line on a velocity versus time graph signifies an accelerated motion. Since a free-falling object is undergoing an acceleration (g = 9,8 m/s/s, downward), it would be expected that its velocity-time graph would be diagonal. A further look at the velocity-time graph reveals that the object starts with a zero velocity (as read from the graph) and finishes with a large, negative velocity; that is, the object is moving in the negative direction and speeding up. An object that is moving in the negative direction and speeding up is said to have a negative acceleration (if necessary, review the vector nature of acceleration). Since the slope of any velocity versus time graph is the acceleration of the object (as learned in Lesson 4), the constant, negative slope indicates a constant, negative acceleration. This analysis of the slope on the graph is consistent with the motion of a free-falling object - an object moving with a constant acceleration of 9.8 m/s/s in the downward direction. The Kinematic Equations The goal of this first unit has been to investigate the variety of means by which the motion of objects can be described. The variety of representations that we have investigated includes verbal representations, pictorial representations, numerical representations, and graphical representations (position-time graphs and velocity-time graphs). In Lesson 6, we will investigate the use of equations to describe and represent the motion of objects. These equations are known as kinematic equations. There are a variety of quantities associated with the motion of objects - displacement (and distance), velocity (and speed), acceleration, and time. Knowledge of each of these quantities provides descriptive information about an object's motion. For example, if a car is known to move with a constant velocity of 22.0 m/s, North for 12.0 seconds for a northward displacement of 264 meters, then the motion of the car is fully described. And if a second car is known to accelerate from a rest position with an eastward acceleration of 3.0 m/s2 for a time of 8.0 seconds, providing a final velocity of 24 m/s, East and an eastward displacement of 96 meters, then the motion of this car is fully described. These two statements provide a complete description of the motion of an object. However, such completeness is not always known. It is often the case that only a few parameters of an object's motion are known, while the rest are unknown. For example as you approach the stoplight, you might know that your car has a velocity of 22 m/s, East and is capable of a skidding acceleration of 8.0 m/s2, West. However you do not know the displacement that your car would experience if you were to slam on your brakes and skid to a stop; and you do not know the time required to skid to a stop. In such an instance as this, the unknown parameters can be determined using physics principles and mathematical equations (the kinematic equations). The BIG 4 The kinematic equations are a set of four equations that can be utilized to predict unknown information about an object's motion if other information is known. The equations can be utilized for any motion that can be described as being either a constant velocity motion (an acceleration of 0 m/s/s) or a constant acceleration motion. They can never be used over any time period during which the acceleration is changing. Each of the kinematic equations include four variables. If the values of three of the four variables are known, then the value of the fourth variable can be calculated. In this manner, the kinematic equations provide a useful means of predicting information about an object's motion if other information is known. For example, if the acceleration value and the initial and final velocity values of a skidding car is known, then the displacement of the car and the time can be predicted using the kinematic equations. Lesson 6 of this unit will focus upon the use of the kinematic equations to predict the numerical values of unknown quantities for an object's motion. The four kinematic equations that describe an object's motion are: There are a variety of symbols used in the above equations. Each symbol has its own specific meaning. The symbol d stands for the displacement of the object. The symbol t stands for the time for which the object moved. The symbol a stands for the acceleration of the object. And the symbol v stands for the velocity of the object; a subscript of i after the v (as in vi) indicates that the velocity value is the initial velocity value and a subscript of f (as in vf) indicates that the velocity value is the final velocity value. Each of these four equations appropriately describes the mathematical relationship between the parameters of an object's motion. As such, they can be used to predict unknown information about an object's motion if other information is known. In the next part of Lesson 6 we will investigate the process of doing this. Kinematic Equations and Problem-Solving The four kinematic equations that describe the mathematical relationship between the parameters that describe an object's motion were introduced in the previous part of Lesson 6. The four kinematic equations are: In the above equations, the symbol d stands for the displacement of the object. The symbol t stands for the time for which the object moved. The symbol a stand for the acceleration of the object. And the symbol v stands for the instantaneous velocity of the object; a subscript of i after the v (as in vi) indicates that the velocity value is the initial velocity value and a subscript of f (as in vf) indicates that the velocity value is the final velocity value. Problem-Solving Strategy In this part of Lesson 6 we will investigate the process of using the equations to determine unknown information about an object's motion. The process involves the use of a problem-solving strategy that will be used throughout the course. The strategy involves the following steps: 1. Construct an informative diagram of the physical situation. 2. Identify and list the given information in variable form. 3. Identify and list the unknown information in variable form. 4. Identify and list the equation that will be used to determine unknown information from known information. 5. Substitute known values into the equation and use appropriate algebraic steps to solve for the unknown information. 6. Check your answer to ensure that it is reasonable and mathematically correct. The use of this problem-solving strategy in the solution of the following problem is modeled in Examples A and B below. Example Problem A . Ima Hurryin is approaching a stoplight moving with a velocity of +30.0 m/s. The light turns yellow, and Ima applies the brakes and skids to a stop. If Ima's acceleration is -8.00 m/s2, then determine the displacement of the car during the skidding process. (Note that the direction of the velocity and the acceleration vectors are denoted by a + and a - sign.) The solution to this problem begins by the construction of an informative diagram of the physical situation. This is shown below. The second step involves the identification and listing of known information in variable form. Note that the vf value can be inferred to be 0 m/s since Ima's car comes to a stop. The initial velocity (vi) of the car is +30.0 m/s since this is the velocity at the beginning of the motion (the skidding motion). And the acceleration (a) of the car is given as - 8.00 m/s2. (Always pay careful attention to the + and - signs for the given quantities.) The next step of the strategy involves the listing of the unknown (or desired) information in variable form. In this case, the problem requests information about the displacement of the car. So d is the unknown quantity. The results of the first three steps are shown in the table below. Diagram: Given: Find: vi = +30.0 m/s vf = 0 m/s a = - 8.00 m/s2 d = ?? The next step of the strategy involves identifying a kinematic equation that would allow you to determine the unknown quantity. There are four kinematic equations to choose from. In general, you will always choose the equation that contains the three known and the one unknown variable. In this specific case, the three known variables and the one unknown variable are vf, vi, a, and d. Thus, you will look for an equation that has these four variables listed in it. An inspection of the four equations above reveals that the equation on the top right contains all four variables. vf2 = vi2 + 2 ⢠a ⢠d Once the equation is identified and written down, the next step of the strategy involves substituting known values into the equation and using proper algebraic steps to solve for the unknown information. This step is shown below. (0 m/s)2 = (30.0 m/s)2 + 2 ⢠(-8.00 m/s2) ⢠d 0 m2/s2 = 900 m2/s2 + (-16.0 m/s2) ⢠d (16.0 m/s2) ⢠d = 900 m2/s2 - 0 m2/s2 (16.0 m/s2)*d = 900 m2/s2 d = (900 m2/s2)/ (16.0 m/s2) d = (900 m2/s2)/ (16.0 m/s2) d = 56.3 m The solution above reveals that the car will skid a distance of 56.3 meters. (Note that this value is rounded to the third digit.) The last step of the problem-solving strategy involves checking the answer to assure that it is both reasonable and accurate. The value seems reasonable enough. It takes a car a considerable distance to skid from 30.0 m/s (approximately 65 mi/hr) to a stop. The calculated distance is approximately one-half a football field, making this a very reasonable skidding distance. Checking for accuracy involves substituting the calculated value back into the equation for displacement and insuring that the left side of the equation is equal to the right side of the equation. Indeed it is! Example Problem B Ben Rushin is waiting at a stoplight. When it finally turns green, Ben accelerated from rest at a rate of a 6.00 m/s2 for a time of 4.10 seconds. Determine the displacement of Ben's car during this time period. Once more, the solution to this problem begins by the construction of an informative diagram of the physical situation. This is shown below. The second step of the strategy involves the identification and listing of known information in variable form. Note that the vi value can be inferred to be 0 m/s since Ben's car is initially at rest. The acceleration (a) of the car is 6.00 m/s2. And the time (t) is given as 4.10 s. The next step of the strategy involves the listing of the unknown (or desired) information in variable form. In this case, the problem requests information about the displacement of the car. So d is the unknown information. The results of the first three steps are shown in the table below. Diagram: Given: Find: vi = 0 m/s t = 4.10 s a = 6.00 m/s2 d = ?? The next step of the strategy involves identifying a kinematic equation that would allow you to determine the unknown quantity. There are four kinematic equations to choose from. Again, you will always search for an equation that contains the three known variables and the one unknown variable. In this specific case, the three known variables and the one unknown variable are t, vi, a, and d. An inspection of the four equations above reveals that the equation on the top left contains all four variables. d = vi ⢠t + ½ ⢠a ⢠t2 Once the equation is identified and written down, the next step of the strategy involves substituting known values into the equation and using proper algebraic steps to solve for the unknown information. This step is shown below. d = (0 m/s) ⢠(4.1 s) + ½ ⢠(6.00 m/s2) ⢠(4.10 s)2 d = (0 m) + ½ ⢠(6.00 m/s2) ⢠(16.81 s2) d = 0 m + 50.43 m d = 50.4 m The solution above reveals that the car will travel a distance of 50.4 meters. (Note that this value is rounded to the third digit.) The last step of the problem-solving strategy involves checking the answer to assure that it is both reasonable and accurate. The value seems reasonable enough. A car with an acceleration of 6.00 m/s/s will reach a speed of approximately 24 m/s (approximately 50 mi/hr) in 4.10 s. The distance over which such a car would be displaced during this time period would be approximately one-half a football field, making this a very reasonable distance. Checking for accuracy involves substituting the calculated value back into the equation for displacement and insuring that the left side of the equation is equal to the right side of the equation. Indeed, it is! The two example problems above illustrate how the kinematic equations can be combined with a simple problem-solving strategy to predict unknown motion parameters for a moving object. Provided that three motion parameters are known, any of the remaining values can be determined. In the next part of Lesson 6, we will see how this strategy can be applied to free fall situations. Or if interested, you can try some practice problems and check your answer against the given solutions. Kinematic Equations and Free Fall As mentioned in Lesson 5, a free-falling object is an object that is falling under the sole influence of gravity. That is to say that any object that is moving and being acted upon only be the force of gravity is said to be "in a state of free fall." Such an object will experience a downward acceleration of 9.8 m/s/s. Whether the object is falling downward or rising upward towards its peak, if it is under the sole influence of gravity, then its acceleration value is 9.8 m/s/s. Like any moving object, the motion of an object in free fall can be described by four kinematic equations. The kinematic equations that describe any object's motion are: The symbols in the above equation have a specific meaning: the symbol d stands for the displacement; the symbol t stands for the time; the symbol a stands for the acceleration of the object; the symbol vi stands for the initial velocity value; and the symbol vf stands for the final velocity. Applying Free Fall Concepts to Problem-Solving There are a few conceptual characteristics of free fall motion that will be of value when using the equations to analyze free fall motion. These concepts are described as follows: ⢠An object in free fall experiences an acceleration of -9.8 m/s/s. (The - sign indicates a downward acceleration.) Whether explicitly stated or not, the value of the acceleration in the kinematic equations is -9.8 m/s/s for any freely falling object. ⢠If an object is merely dropped (as opposed to being thrown) from an elevated height, then the initial velocity of the object is 0 m/s. ⢠If an object is projected upwards in a perfectly vertical direction, then it will slow down as it rises upward. The instant at which it reaches the peak of its trajectory, its velocity is 0 m/s. This value can be used as one of the motion parameters in the kinematic equations; for example, the final velocity (vf) after traveling to the peak would be assigned a value of 0 m/s. ⢠If an object is projected upwards in a perfectly vertical direction, then the velocity at which it is projected is equal in magnitude and opposite in sign to the velocity that it has when it returns to the same height. That is, a ball projected vertically with an upward velocity of +30 m/s will have a downward velocity of -30 m/s when it returns to the same height. These four principles and the four kinematic equations can be combined to solve problems involving the motion of free-falling objects. The two examples below illustrate application of free fall principles to kinematic problem-solving. In each example, the problem solving strategy that was introduced earlier in this lesson will be utilized. Example Problem A Luke Autbeloe drops a pile of roof shingles from the top of a roof located 8.52 meters above the ground. Determine the time required for the shingles to reach the ground. The solution to this problem begins by the construction of an informative diagram of the physical situation. This is shown below. The second step involves the identification and listing of known information in variable form. You might note that in the statement of the problem, there is only one piece of numerical information explicitly stated: 8.52 meters. The displacement (d) of the shingles is -8.52 m. (The - sign indicates that the displacement is downward). The remaining information must be extracted from the problem statement based upon your understanding of the above principles. For example, the vi value can be inferred to be 0 m/s since the shingles are dropped (released from rest; see note above). And the acceleration (a) of the shingles can be inferred to be -9.8 m/s2 since the shingles are free-falling (see note above). (Always pay careful attention to the + and - signs for the given quantities.) The next step of the solution involves the listing of the unknown (or desired) information in variable form. In this case, the problem requests information about the time of fall. So t is the unknown quantity. The results of the first three steps are shown in the table below. Diagram: Given: Find: vi = 0.0 m/s d = -8.52 m a = - 9.8 m/s2 t = ?? The next step involves identifying a kinematic equation that allows you to determine the unknown quantity. There are four kinematic equations to choose from. In general, you will always choose the equation that contains the three known and the one unknown variable. In this specific case, the three known variables and the one unknown variable are d, vi, a, and t. Thus, you will look for an equation that has these four variables listed in it. An inspection of the four equations above reveals that the equation on the top left contains all four variables. d = vi ⢠t + ½ ⢠a ⢠t2 Once the equation is identified and written down, the next step involves substituting known values into the equation and using proper algebraic steps to solve for the unknown information. This step is shown below. -8.52 m = (0 m/s) ⢠(t) + ½ ⢠(-9.8 m/s2) ⢠(t)2 -8.52 m = (0 m) *(t) + (-4.9 m/s2) ⢠(t)2 -8.52 m = (-4.9 m/s2) ⢠(t)2 (-8.52 m)/(-4.9 m/s2) = t2 1.739 s2 = t2 t = 1.32 s The solution above reveals that the shingles will fall for a time of 1.32 seconds before hitting the ground. (Note that this value is rounded to the third digit.) The last step of the problem-solving strategy involves checking the answer to assure that it is both reasonable and accurate. The value seems reasonable enough. The shingles are falling a distance of approximately 10 yards (1 meter is pretty close to 1 yard); it seems that an answer between 1 and 2 seconds would be highly reasonable. The calculated time easily falls within this range of reasonability. Checking for accuracy involves substituting the calculated value back into the equation for time and insuring that the left side of the equation is equal to the right side of the equation. Indeed it is! Example Problem B Rex Things throws his mother's crystal vase vertically upwards with an initial velocity of 26.2 m/s. Determine the height to which the vase will rise above its initial height. Once more, the solution to this problem begins by the construction of an informative diagram of the physical situation. This is shown below. The second step involves the identification and listing of known information in variable form. You might note that in the statement of the problem, there is only one piece of numerical information explicitly stated: 26.2 m/s. The initial velocity (vi) of the vase is +26.2 m/s. (The + sign indicates that the initial velocity is an upwards velocity). The remaining information must be extracted from the problem statement based upon your understanding of the above principles. Note that the vf value can be inferred to be 0 m/s since the final state of the vase is the peak of its trajectory (see note above). The acceleration (a) of the vase is -9.8 m/s2 (see note above). The next step involves the listing of the unknown (or desired) information in variable form. In this case, the problem requests information about the displacement of the vase (the height to which it rises above its starting height). So d is the unknown information. The results of the first three steps are shown in the table below. Diagram: Given: Find: vi = 26.2 m/s vf = 0 m/s a = -9.8 m/s2 d = ?? The next step involves identifying a kinematic equation that would allow you to determine the unknown quantity. There are four kinematic equations to choose from. Again, you will always search for an equation that contains the three known variables and the one unknown variable. In this specific case, the three known variables and the one unknown variable are vi, vf, a, and d. An inspection of the four equations above reveals that the equation on the top right contains all four variables. vf2 = vi2 + 2 ⢠a ⢠d Once the equation is identified and written down, the next step involves substituting known values into the equation and using proper algebraic steps to solve for the unknown information. This step is shown below. (0 m/s)2 = (26.2 m/s)2 + 2 â˘(-9.8m/s2) â˘d 0 m2/s2 = 686.44 m2/s2 + (-19.6 m/s2) â˘d (-19.6 m/s2) ⢠d = 0 m2/s2 -686.44 m2/s2 (-19.6 m/s2) ⢠d = -686.44 m2/s2 d = (-686.44 m2/s2)/ (-19.6 m/s2) d = 35.0 m The solution above reveals that the vase will travel upwards for a displacement of 35.0 meters before reaching its peak. (Note that this value is rounded to the third digit.) The last step of the problem-solving strategy involves checking the answer to assure that it is both reasonable and accurate. The value seems reasonable enough. The vase is thrown with a speed of approximately 50 mi/hr (merely approximate 1 m/s to be equivalent to 2 mi/hr). Such a throw will never make it further than one football field in height (approximately 100 m), yet will surely make it past the 10-yard line (approximately 10 meters). The calculated answer certainly falls within this range of reasonability. Checking for accuracy involves substituting the calculated value back into the equation for displacement and insuring that the left side of the equation is equal to the right side of the equation. Indeed, it is! Kinematic equations provide a useful means of determining the value of an unknown motion parameter if three motion parameters are known. In the case of a free-fall motion, the acceleration is often known. And in many cases, another motion parameter can be inferred through a solid knowledge of some basic kinematic principles.
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