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THINGS IN THE CLASSROOM
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Where places are located?, places in the school, things in the classroom and prepositions of place. (*Vocabulary / Grammar)In our classroom, we believe in teamwork and responsibility. That's why we have different classroom jobs that students can take on to help make our learning environment run smoothly. Each job comes with specific tasks and responsibilities, and it is important for the students to understand the requirements and expectations for each role. Let's take a closer look at the different classroom jobs available to our sixth-grade students: 1. Teacher's Assistant: The Teacher's Assistant plays a crucial role in our classroom. Their main responsibility is to remind the teacher of important tasks that need to be done throughout the day. This includes taking attendance, passing out papers to go home, and any other "do not forget" tasks that the teacher might need help with. The Teacher's Assistant needs to be organized, responsible, and reliable. 2. Supplies Monitor: The Supplies Monitor is responsible for ensuring that all classroom supplies are put away neatly. This includes making sure that pencils, pens, markers, and other materials are returned to their designated places after each use. The Supplies Monitor needs to be attentive to detail and have good organizational skills. 3. Technology Assistant: With our use of technology in the classroom, the Technology Assistant plays a vital role. They help students and guest teachers who might not be tech-savvy with chromebooks and other devices. The Technology Assistant should be comfortable with technology, patient, and willing to help others. 4. Room Monitor: The Room Monitor is in charge of checking desks and floors before lunch dismissal. They make sure that everything is clean and organized before we leave the classroom. The Room Monitor needs to be responsible, observant, and take pride in maintaining a tidy learning environment. 5. Line Leader: The Line Leader has the important task of leading the class and setting the pace when we transition from one place to another. They need to walk in a straight line, follow instructions, and be a positive role model for their peers. The Line Leader should be reliable, responsible, and demonstrate good leadership skills. 6. Messenger: The Messenger is responsible for taking things to the office or picking up items that the teacher needs. They need to be trustworthy, reliable, and able to follow instructions. The Messenger should also have good time management skills to ensure tasks are completed promptly. 7. Host/Hostess: When visitors come to our classroom and need assistance while the teacher is busy, the Host/Hostess is there to help. They greet visitors, provide directions, and offer any necessary support. The Host/Hostess should have good communication skills, be friendly, and approachable. 8. Guest Teacher Guide: In the event of a guest teacher, this student will help them take attendance and assist the teacher with anything they need help with. The Guest Teacher Guide needs to be responsible, reliable, and have good communication skills. They should also be respectful and supportive of the guest teacher. 9. Researcher: During whole-class discussions, if there is a question or topic that needs further exploration, the Researcher steps in. They use the internet to look up information and provide additional insights. The Researcher should have good research skills, be able to navigate online resources, and share accurate information with the class. 10. Secretary: The Secretary takes down notes when directed in the class notebook and collects any papers for absent students, placing them in their designated file. They need to be organized, attentive, and have good handwriting. It is important to note that all of these roles come with certain requirements. To be considered for any of these jobs, you must be punctual and have good attendance. This means arriving to school and class on time every day. Additionally, honesty and reliability are crucial traits for anyone taking on these responsibilities. By working together and taking on these classroom jobs, we can create an environment that is conducive to learning, organized, and supportive. Each of these roles plays a vital part in our classroom community, and we appreciate the efforts of all students who take on these responsibilities. Let's make our classroom a place where everyone feels valued and can thrive!Create multiple choice questions using the following information: In November, Mrs. Baker has Holling read The Tempest. Despite his preconceptions, Holling is captivated by all the "good stuff" in the play, especially the cussing, which he decides to learn by heart. He figures that Mrs. Baker could not have read the play herself; if she had, she certainly would not have let him have it. Holling is amazed when he discovers that his teacher not only has read the play, but she knows the bad parts as well. Mrs. Baker gives Holling a one-hundred-and-fifty question test on The Tempest, and assigns him to read the play again, telling him "there is a lot more to (it) than a list of colorful curses." The deadline set by Holling's classmates for him to bring them cream puffs arrives, but although Holling's father's company has won the Baker's Sporting Emporium contract, he refuses to extend an advance on his son's allowance. Desperate, Holling goes to Goldman's Best Bakery, offering to work for the money he lacks to buy the cream puffs. Coincidentally, Mr. Goldman, who is active in Long Island's Shakespeare Company, needs a boy to perform in their upcoming Extravaganza, and because of his work with Mrs. Baker, Holling fits the bill. Mr. Goldman gives Holling the required number of cream puffs in exchange, but sadly, while the students are at recess, Caliban and Sycorax, the escaped rats who inhabit the classroom walls and ceiling, come out and decimate the treats. Somehow, the disaster is blamed on Holling; he must clean up the mess, and his classmates decree that he still owes them cream puffs. The next Wednesday, Holling brings five cream puffs to school, which is all he can afford. In addition to facing his classmates' ire, he has to deal with the fact that, in the Shakespeare Company Holiday Extravaganza, he must play the part of Ariel, who is a fairy, and wear yellow tights with white feathers on an unmentionable part of his anatomy; "not a good thing for a boy from Camillo Junior High." To Holling's surprise, just when things are at their darkest, Mrs. Baker comes through for him, bringing cream puffs for the students on his behalf. That afternoon, Mrs. Baker and Holling discuss The Tempest, and whether or not Caliban, the "monster," deserves a happy ending. Holling argues that, as the antagonist, he does not, but Mrs. Baker muses whether Shakespeare might have shown, even in a monster, the capacity of humankind to use defeat to grow. Mrs. Bigio stumbles into the classroom at this point, emitting sounds of indescribable sadness; she has just learned that her husband has been killed in a futile reconnaissance mission in Vietnam. Two nights after his funeral, the Catholic Relief Agency, which houses Vietnamese refugees, including Holling's classmate Mai Thi, is the target of a hate crime. Holling reflects that Shakespeare, with his happy endings for nearly everyone in The Tempest, is wrong. He says, "sometimes, there isn't a Prospero to make everything fine...and...the quality of mercy is strained." In December, Camillo Junior High is awash in "signs of the season." Mrs. Baker, however, does not share the holiday spirit, but Holling is too absorbed with his problems with the Shakespeare Holiday Extravaganza to wonder why. As always, Holling seeks help from his family, but to no avail; his mother comments insipidly that his embarrassing costume is cute, his father tells him to wear it to please Mr. Goldman, who might one day need an architect, and his sister warns him that if news of his role gets to the high school, no one better find out they are related. The only thing that prevents December from being a total disaster is Mrs. Baker's announcement that Mickey Mantle will be signing autographs at the Baker Sporting Emporium. Unfortunately, Mrs. Baker also tells the class about Holling and the Shakespeare Extravaganza, and encourages the students to attend both events. Holling's classmates are intensely curious about his role as Ariel, whom he euphemistically describes as "a warrior." Mr. Goldman tells Mrs. Baker that Holling needs "some practice on interpretation", and she practices with him, playing the part of Prospero. Mrs. Baker is a terrific reader, and when she and Holling rehearse the part where Prospero releases Ariel from bondage, Holling is inspired, realizing what it means to be free "to create his own happy ending." On the night of the performance, Mrs. Baker, Mrs. Bigio, Danny Hupfer and his parents, Meryl Lee, and Mai Thi are in the audience to support Holling, unlike his own parents, who do not want to miss the Bing Crosby Christmas Special on television. Holling executes his part with such passion that his classmates are moved to tears, and do not even notice what he is wearing. When the show is over, Holling, finding the dressing room locked, rushes outside, still in costume, where his father is supposed to be waiting to take him to Baker's Sporting Emporium to see Mickey Mantle. Typically, his father is not there, and Holling, frantic, flags down a bus and begs the driver to take him to the Emporium. The driver takes pity on him and complies, getting him to the Emporium just in time, but when Holling approaches Mickey Mantle for an autograph, the famous player looks derisively at his costume and snaps rudely, "I don't sign baseballs for kids in yellow tights." Danny Hupfer witnesses this snub, and loyally returns his own autographed baseball to Mickey Mantle, saying, "I guess I don't need this after all." Holling and Danny leave together in silence, smarting because "when gods die, they die hard." During the days remaining until holiday break, Mrs. Bigio is especially cantankerous; her cafeteria cooking is unappetizing at best, and her comments to the students are impatient and unkind. Holling, remembering Mrs. Bigio's sadness when she received the news of her husband's death, does not complain, but he is bewildered at the sheer desolation he witnesses when Mrs. Bigio bitterly tells Mai Thi that she "shouldn't even be here...a queen in a refugee home while American boys are sitting in swamps on Christmas Day." After school on the last day before break, Mrs. Baker gives Holling, Danny Hupfer, and Doug Swieteck each a new baseball and mitt, and sends them to the gym, where, to their delight, they meet Joe Pepitone and Horace Clark in their Yankee uniforms, and receive tickets to Opening Day at the Stadium. Mrs. Baker's family knows what happened with Mickey Mantle, and wants to make it up to the boys. The next day, President Johnson declares a Christmas ceasefire in Vietnam, and the holiday season begins in earnest.Memory Adventure: From Learning to Forgetting Imagine Alex is preparing for a school science fair. Storing Memories (2.5) Alex studies a science experiment. The semantic memory (facts and knowledge, like “water boils at 100°C”) is stored in the brain, while episodic memory (personal experiences, like “I mixed vinegar and baking soda yesterday”) records the event. The hippocampus (the brain’s “save button”) helps transfer these memories into long-term memory. During sleep, memory consolidation (making memories stable and long-lasting) happens, and Alex vividly remembers the fun surprise when the mixture fizzes—a flashbulb memory (emotionally strong, vivid memory). Alex also learns the skill of carefully pouring liquids, a procedural memory stored in the basal ganglia, and how to react when the mixture splashes, a conditioned response stored in the cerebellum. Emotions make the memory even stronger, thanks to the amygdala. Retrieving Memories (2.6) The next day, Alex goes to the science fair. Seeing the experiment table triggers priming (unconscious memory activation—seeing the table makes Alex remember steps). Being in the same classroom helps context-dependent memory (better recall in the same place as learning). Alex is also in the same excited mood as while practicing, so mood-congruent memory helps remember details of the experiment. When listing the steps, Alex remembers the first step clearly and the last step best, thanks to the serial position effect. Using strategies like quizzing himself earlier (testing effect) and spacing study sessions (spacing effect) improves retrieval. Forgetting & Memory Errors (2.7) During the fair, Alex tries to remember an old trick learned last year, but some details are fuzzy. This is retroactive interference (new memories block old ones). At the same time, old steps from last year sometimes confuse him, an example of proactive interference (old memories block new info). Alex’s friend jokingly says he added glitter to the experiment last week. Alex later misremembers seeing glitter—this is the misinformation effect. He even forgets where he first learned the correct steps, a case of source amnesia, and feels a strange sense of déjà vu when looking at a similar experiment table. Unfortunately, Alex’s cousin has anterograde amnesia (cannot form new memories) and can only remember things from before last year, while his neighbor has retrograde amnesia (loses past memories) and cannot recall last week’s fair prep. Luckily, Alex’s strong study habits, sleep, and emotional engagement helped protect his memories from being forgotten too quickly.Introduction to Free Fall A free-falling object is an object that is falling under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. There are two important motion characteristics that are true of free-falling objects: • Free-falling objects do not encounter air resistance. • All free-falling objects (on Earth) accelerate downwards at a rate of 9.8 m/s/s (often approximated as 10 m/s/s for back-of-the-envelope calculations) Because free-falling objects are accelerating downwards at a rate of 9.8 m/s/s, a ticker tape trace or dot diagram of its motion would depict an acceleration. The dot diagram at the right depicts the acceleration of a free-falling object. The position of the object at regular time intervals - say, every 0.1 second - is shown. The fact that the distance that the object travels every interval of time is increasing is a sure sign that the ball is speeding up as it falls downward. Recall from an earlier lesson, that if an object travels downward and speeds up, then its acceleration is downward. Free-fall acceleration is often witnessed in a physics classroom by means of an ever-popular strobe light demonstration. The room is darkened and a jug full of water is connected by a tube to a medicine dropper. The dropper drips water and the strobe illuminate the falling droplets at a regular rate - say once every 0.2 seconds. Instead of seeing a stream of water free-falling from the medicine dropper, several consecutive drops with increasing separation distance are seen. The pattern of drops resembles the dot diagram shown in the graphic at the right. The Acceleration of Gravity It was learned in the previous part of this lesson that a free-falling object is an object that is falling under the sole influence of gravity. A free-falling object has an acceleration of 9.8 m/s/s, downward (on Earth). This numerical value for the acceleration of a free-falling object is such an important value that it is given a special name. It is known as the acceleration of gravity - the acceleration for any object moving under the sole influence of gravity. A matter of fact, this quantity known as the acceleration of gravity is such an important quantity that physicists have a special symbol to denote it - the symbol g. The numerical value for the acceleration of gravity is most accurately known as 9.8 m/s2. There are slight variations in this numerical value (to the second decimal place) that are dependent primarily upon on altitude. We will occasionally use the approximated value of 10 m/s2 in order to reduce the complexity of the many mathematical tasks that we will perform with this number. By so doing, we will be able to better focus on the conceptual nature of physics without too much of a sacrifice in numerical accuracy. g = 9.8 m/s2, downward Look It Up! Even on the surface of the Earth, there are local variations in the value of the acceleration of gravity (g). These variations are due to latitude, altitude and the local geological structure of the region. Recall from an earlier lesson that acceleration is the rate at which an object changes its velocity. It is the ratio of velocity change to time between any two points in an object's path. To accelerate at 9.8 m/s2 means to change the velocity by 9.8 m/s each second. If the velocity and time for a free-falling object being dropped from a position of rest were tabulated, then one would note the following pattern. Time (s) Velocity (m/s) 0 0 1 - 9.8 2 - 19.6 3 - 29.4 4 - 39.2 5 - 49.0 . Observe that the velocity-time data above reveal that the object's velocity is changing by 9.8 m/s each consecutive second. That is, the free-falling object has an acceleration of approximately 9.8 m/s2. Another way to represent this acceleration of 9.8 m/s2 is to add numbers to our dot diagram that we saw earlier in this lesson. The velocity of the ball is seen to increase as depicted in the diagram at the right. (NOTE: The diagram is not drawn to scale - in two seconds, the object would drop considerably further than the distance from shoulder to toes.) Representing Free Fall by Graphs • Early in Lesson 1 it was mentioned that there are a variety of means of describing the motion of objects. One such means of describing the motion of objects is through the use of graphs - position versus time and velocity vs. time graphs. In this part of Lesson 5, the motion of a free-falling motion will be represented using these two basic types of graphs. Representing Free Fall by Position-Time Graphs A position versus time graph for a free-falling object is shown below. Observe that the line on the graph curves. As learned earlier, a curved line on a position versus time graph signifies an accelerated motion. Since a free-falling object is undergoing an acceleration (g = 9.8 m/s/s), it would be expected that its position-time graph would be curved. A further look at the position-time graph reveals that the object starts with a small velocity (slow) and finishes with a large velocity (fast). Since the slope of any position vs. time graph is the velocity of the object (as learned in Lesson 3), the small initial slope indicates a small initial velocity and the large final slope indicates a large final velocity. Finally, the negative slope of the line indicates a negative (i.e., downward) velocity. Representing Free Fall by Velocity-Time Graphs A velocity versus time graph for a free-falling object is shown below. Observe that the line on the graph is a straight, diagonal line. As learned earlier, a diagonal line on a velocity versus time graph signifies an accelerated motion. Since a free-falling object is undergoing an acceleration (g = 9,8 m/s/s, downward), it would be expected that its velocity-time graph would be diagonal. A further look at the velocity-time graph reveals that the object starts with a zero velocity (as read from the graph) and finishes with a large, negative velocity; that is, the object is moving in the negative direction and speeding up. An object that is moving in the negative direction and speeding up is said to have a negative acceleration (if necessary, review the vector nature of acceleration). Since the slope of any velocity versus time graph is the acceleration of the object (as learned in Lesson 4), the constant, negative slope indicates a constant, negative acceleration. This analysis of the slope on the graph is consistent with the motion of a free-falling object - an object moving with a constant acceleration of 9.8 m/s/s in the downward direction. The Kinematic Equations The goal of this first unit has been to investigate the variety of means by which the motion of objects can be described. The variety of representations that we have investigated includes verbal representations, pictorial representations, numerical representations, and graphical representations (position-time graphs and velocity-time graphs). In Lesson 6, we will investigate the use of equations to describe and represent the motion of objects. These equations are known as kinematic equations. There are a variety of quantities associated with the motion of objects - displacement (and distance), velocity (and speed), acceleration, and time. Knowledge of each of these quantities provides descriptive information about an object's motion. For example, if a car is known to move with a constant velocity of 22.0 m/s, North for 12.0 seconds for a northward displacement of 264 meters, then the motion of the car is fully described. And if a second car is known to accelerate from a rest position with an eastward acceleration of 3.0 m/s2 for a time of 8.0 seconds, providing a final velocity of 24 m/s, East and an eastward displacement of 96 meters, then the motion of this car is fully described. These two statements provide a complete description of the motion of an object. However, such completeness is not always known. It is often the case that only a few parameters of an object's motion are known, while the rest are unknown. For example as you approach the stoplight, you might know that your car has a velocity of 22 m/s, East and is capable of a skidding acceleration of 8.0 m/s2, West. However you do not know the displacement that your car would experience if you were to slam on your brakes and skid to a stop; and you do not know the time required to skid to a stop. In such an instance as this, the unknown parameters can be determined using physics principles and mathematical equations (the kinematic equations). The BIG 4 The kinematic equations are a set of four equations that can be utilized to predict unknown information about an object's motion if other information is known. The equations can be utilized for any motion that can be described as being either a constant velocity motion (an acceleration of 0 m/s/s) or a constant acceleration motion. They can never be used over any time period during which the acceleration is changing. Each of the kinematic equations include four variables. If the values of three of the four variables are known, then the value of the fourth variable can be calculated. In this manner, the kinematic equations provide a useful means of predicting information about an object's motion if other information is known. For example, if the acceleration value and the initial and final velocity values of a skidding car is known, then the displacement of the car and the time can be predicted using the kinematic equations. Lesson 6 of this unit will focus upon the use of the kinematic equations to predict the numerical values of unknown quantities for an object's motion. The four kinematic equations that describe an object's motion are: There are a variety of symbols used in the above equations. Each symbol has its own specific meaning. The symbol d stands for the displacement of the object. The symbol t stands for the time for which the object moved. The symbol a stands for the acceleration of the object. And the symbol v stands for the velocity of the object; a subscript of i after the v (as in vi) indicates that the velocity value is the initial velocity value and a subscript of f (as in vf) indicates that the velocity value is the final velocity value. Each of these four equations appropriately describes the mathematical relationship between the parameters of an object's motion. As such, they can be used to predict unknown information about an object's motion if other information is known. In the next part of Lesson 6 we will investigate the process of doing this. Kinematic Equations and Problem-Solving The four kinematic equations that describe the mathematical relationship between the parameters that describe an object's motion were introduced in the previous part of Lesson 6. The four kinematic equations are: In the above equations, the symbol d stands for the displacement of the object. The symbol t stands for the time for which the object moved. The symbol a stand for the acceleration of the object. And the symbol v stands for the instantaneous velocity of the object; a subscript of i after the v (as in vi) indicates that the velocity value is the initial velocity value and a subscript of f (as in vf) indicates that the velocity value is the final velocity value. Problem-Solving Strategy In this part of Lesson 6 we will investigate the process of using the equations to determine unknown information about an object's motion. The process involves the use of a problem-solving strategy that will be used throughout the course. The strategy involves the following steps: 1. Construct an informative diagram of the physical situation. 2. Identify and list the given information in variable form. 3. Identify and list the unknown information in variable form. 4. Identify and list the equation that will be used to determine unknown information from known information. 5. Substitute known values into the equation and use appropriate algebraic steps to solve for the unknown information. 6. Check your answer to ensure that it is reasonable and mathematically correct. The use of this problem-solving strategy in the solution of the following problem is modeled in Examples A and B below. Example Problem A . Ima Hurryin is approaching a stoplight moving with a velocity of +30.0 m/s. The light turns yellow, and Ima applies the brakes and skids to a stop. If Ima's acceleration is -8.00 m/s2, then determine the displacement of the car during the skidding process. (Note that the direction of the velocity and the acceleration vectors are denoted by a + and a - sign.) The solution to this problem begins by the construction of an informative diagram of the physical situation. This is shown below. The second step involves the identification and listing of known information in variable form. Note that the vf value can be inferred to be 0 m/s since Ima's car comes to a stop. The initial velocity (vi) of the car is +30.0 m/s since this is the velocity at the beginning of the motion (the skidding motion). And the acceleration (a) of the car is given as - 8.00 m/s2. (Always pay careful attention to the + and - signs for the given quantities.) The next step of the strategy involves the listing of the unknown (or desired) information in variable form. In this case, the problem requests information about the displacement of the car. So d is the unknown quantity. The results of the first three steps are shown in the table below. Diagram: Given: Find: vi = +30.0 m/s vf = 0 m/s a = - 8.00 m/s2 d = ?? The next step of the strategy involves identifying a kinematic equation that would allow you to determine the unknown quantity. There are four kinematic equations to choose from. In general, you will always choose the equation that contains the three known and the one unknown variable. In this specific case, the three known variables and the one unknown variable are vf, vi, a, and d. Thus, you will look for an equation that has these four variables listed in it. An inspection of the four equations above reveals that the equation on the top right contains all four variables. vf2 = vi2 + 2 • a • d Once the equation is identified and written down, the next step of the strategy involves substituting known values into the equation and using proper algebraic steps to solve for the unknown information. This step is shown below. (0 m/s)2 = (30.0 m/s)2 + 2 • (-8.00 m/s2) • d 0 m2/s2 = 900 m2/s2 + (-16.0 m/s2) • d (16.0 m/s2) • d = 900 m2/s2 - 0 m2/s2 (16.0 m/s2)*d = 900 m2/s2 d = (900 m2/s2)/ (16.0 m/s2) d = (900 m2/s2)/ (16.0 m/s2) d = 56.3 m The solution above reveals that the car will skid a distance of 56.3 meters. (Note that this value is rounded to the third digit.) The last step of the problem-solving strategy involves checking the answer to assure that it is both reasonable and accurate. The value seems reasonable enough. It takes a car a considerable distance to skid from 30.0 m/s (approximately 65 mi/hr) to a stop. The calculated distance is approximately one-half a football field, making this a very reasonable skidding distance. Checking for accuracy involves substituting the calculated value back into the equation for displacement and insuring that the left side of the equation is equal to the right side of the equation. Indeed it is! Example Problem B Ben Rushin is waiting at a stoplight. When it finally turns green, Ben accelerated from rest at a rate of a 6.00 m/s2 for a time of 4.10 seconds. Determine the displacement of Ben's car during this time period. Once more, the solution to this problem begins by the construction of an informative diagram of the physical situation. This is shown below. The second step of the strategy involves the identification and listing of known information in variable form. Note that the vi value can be inferred to be 0 m/s since Ben's car is initially at rest. The acceleration (a) of the car is 6.00 m/s2. And the time (t) is given as 4.10 s. The next step of the strategy involves the listing of the unknown (or desired) information in variable form. In this case, the problem requests information about the displacement of the car. So d is the unknown information. The results of the first three steps are shown in the table below. Diagram: Given: Find: vi = 0 m/s t = 4.10 s a = 6.00 m/s2 d = ?? The next step of the strategy involves identifying a kinematic equation that would allow you to determine the unknown quantity. There are four kinematic equations to choose from. Again, you will always search for an equation that contains the three known variables and the one unknown variable. In this specific case, the three known variables and the one unknown variable are t, vi, a, and d. An inspection of the four equations above reveals that the equation on the top left contains all four variables. d = vi • t + ½ • a • t2 Once the equation is identified and written down, the next step of the strategy involves substituting known values into the equation and using proper algebraic steps to solve for the unknown information. This step is shown below. d = (0 m/s) • (4.1 s) + ½ • (6.00 m/s2) • (4.10 s)2 d = (0 m) + ½ • (6.00 m/s2) • (16.81 s2) d = 0 m + 50.43 m d = 50.4 m The solution above reveals that the car will travel a distance of 50.4 meters. (Note that this value is rounded to the third digit.) The last step of the problem-solving strategy involves checking the answer to assure that it is both reasonable and accurate. The value seems reasonable enough. A car with an acceleration of 6.00 m/s/s will reach a speed of approximately 24 m/s (approximately 50 mi/hr) in 4.10 s. The distance over which such a car would be displaced during this time period would be approximately one-half a football field, making this a very reasonable distance. Checking for accuracy involves substituting the calculated value back into the equation for displacement and insuring that the left side of the equation is equal to the right side of the equation. Indeed, it is! The two example problems above illustrate how the kinematic equations can be combined with a simple problem-solving strategy to predict unknown motion parameters for a moving object. Provided that three motion parameters are known, any of the remaining values can be determined. In the next part of Lesson 6, we will see how this strategy can be applied to free fall situations. Or if interested, you can try some practice problems and check your answer against the given solutions. Kinematic Equations and Free Fall As mentioned in Lesson 5, a free-falling object is an object that is falling under the sole influence of gravity. That is to say that any object that is moving and being acted upon only be the force of gravity is said to be "in a state of free fall." Such an object will experience a downward acceleration of 9.8 m/s/s. Whether the object is falling downward or rising upward towards its peak, if it is under the sole influence of gravity, then its acceleration value is 9.8 m/s/s. Like any moving object, the motion of an object in free fall can be described by four kinematic equations. The kinematic equations that describe any object's motion are: The symbols in the above equation have a specific meaning: the symbol d stands for the displacement; the symbol t stands for the time; the symbol a stands for the acceleration of the object; the symbol vi stands for the initial velocity value; and the symbol vf stands for the final velocity. Applying Free Fall Concepts to Problem-Solving There are a few conceptual characteristics of free fall motion that will be of value when using the equations to analyze free fall motion. These concepts are described as follows: • An object in free fall experiences an acceleration of -9.8 m/s/s. (The - sign indicates a downward acceleration.) Whether explicitly stated or not, the value of the acceleration in the kinematic equations is -9.8 m/s/s for any freely falling object. • If an object is merely dropped (as opposed to being thrown) from an elevated height, then the initial velocity of the object is 0 m/s. • If an object is projected upwards in a perfectly vertical direction, then it will slow down as it rises upward. The instant at which it reaches the peak of its trajectory, its velocity is 0 m/s. This value can be used as one of the motion parameters in the kinematic equations; for example, the final velocity (vf) after traveling to the peak would be assigned a value of 0 m/s. • If an object is projected upwards in a perfectly vertical direction, then the velocity at which it is projected is equal in magnitude and opposite in sign to the velocity that it has when it returns to the same height. That is, a ball projected vertically with an upward velocity of +30 m/s will have a downward velocity of -30 m/s when it returns to the same height. These four principles and the four kinematic equations can be combined to solve problems involving the motion of free-falling objects. The two examples below illustrate application of free fall principles to kinematic problem-solving. In each example, the problem solving strategy that was introduced earlier in this lesson will be utilized. Example Problem A Luke Autbeloe drops a pile of roof shingles from the top of a roof located 8.52 meters above the ground. Determine the time required for the shingles to reach the ground. The solution to this problem begins by the construction of an informative diagram of the physical situation. This is shown below. The second step involves the identification and listing of known information in variable form. You might note that in the statement of the problem, there is only one piece of numerical information explicitly stated: 8.52 meters. The displacement (d) of the shingles is -8.52 m. (The - sign indicates that the displacement is downward). The remaining information must be extracted from the problem statement based upon your understanding of the above principles. For example, the vi value can be inferred to be 0 m/s since the shingles are dropped (released from rest; see note above). And the acceleration (a) of the shingles can be inferred to be -9.8 m/s2 since the shingles are free-falling (see note above). (Always pay careful attention to the + and - signs for the given quantities.) The next step of the solution involves the listing of the unknown (or desired) information in variable form. In this case, the problem requests information about the time of fall. So t is the unknown quantity. The results of the first three steps are shown in the table below. Diagram: Given: Find: vi = 0.0 m/s d = -8.52 m a = - 9.8 m/s2 t = ?? The next step involves identifying a kinematic equation that allows you to determine the unknown quantity. There are four kinematic equations to choose from. In general, you will always choose the equation that contains the three known and the one unknown variable. In this specific case, the three known variables and the one unknown variable are d, vi, a, and t. Thus, you will look for an equation that has these four variables listed in it. An inspection of the four equations above reveals that the equation on the top left contains all four variables. d = vi • t + ½ • a • t2 Once the equation is identified and written down, the next step involves substituting known values into the equation and using proper algebraic steps to solve for the unknown information. This step is shown below. -8.52 m = (0 m/s) • (t) + ½ • (-9.8 m/s2) • (t)2 -8.52 m = (0 m) *(t) + (-4.9 m/s2) • (t)2 -8.52 m = (-4.9 m/s2) • (t)2 (-8.52 m)/(-4.9 m/s2) = t2 1.739 s2 = t2 t = 1.32 s The solution above reveals that the shingles will fall for a time of 1.32 seconds before hitting the ground. (Note that this value is rounded to the third digit.) The last step of the problem-solving strategy involves checking the answer to assure that it is both reasonable and accurate. The value seems reasonable enough. The shingles are falling a distance of approximately 10 yards (1 meter is pretty close to 1 yard); it seems that an answer between 1 and 2 seconds would be highly reasonable. The calculated time easily falls within this range of reasonability. Checking for accuracy involves substituting the calculated value back into the equation for time and insuring that the left side of the equation is equal to the right side of the equation. Indeed it is! Example Problem B Rex Things throws his mother's crystal vase vertically upwards with an initial velocity of 26.2 m/s. Determine the height to which the vase will rise above its initial height. Once more, the solution to this problem begins by the construction of an informative diagram of the physical situation. This is shown below. The second step involves the identification and listing of known information in variable form. You might note that in the statement of the problem, there is only one piece of numerical information explicitly stated: 26.2 m/s. The initial velocity (vi) of the vase is +26.2 m/s. (The + sign indicates that the initial velocity is an upwards velocity). The remaining information must be extracted from the problem statement based upon your understanding of the above principles. Note that the vf value can be inferred to be 0 m/s since the final state of the vase is the peak of its trajectory (see note above). The acceleration (a) of the vase is -9.8 m/s2 (see note above). The next step involves the listing of the unknown (or desired) information in variable form. In this case, the problem requests information about the displacement of the vase (the height to which it rises above its starting height). So d is the unknown information. The results of the first three steps are shown in the table below. Diagram: Given: Find: vi = 26.2 m/s vf = 0 m/s a = -9.8 m/s2 d = ?? The next step involves identifying a kinematic equation that would allow you to determine the unknown quantity. There are four kinematic equations to choose from. Again, you will always search for an equation that contains the three known variables and the one unknown variable. In this specific case, the three known variables and the one unknown variable are vi, vf, a, and d. An inspection of the four equations above reveals that the equation on the top right contains all four variables. vf2 = vi2 + 2 • a • d Once the equation is identified and written down, the next step involves substituting known values into the equation and using proper algebraic steps to solve for the unknown information. This step is shown below. (0 m/s)2 = (26.2 m/s)2 + 2 •(-9.8m/s2) •d 0 m2/s2 = 686.44 m2/s2 + (-19.6 m/s2) •d (-19.6 m/s2) • d = 0 m2/s2 -686.44 m2/s2 (-19.6 m/s2) • d = -686.44 m2/s2 d = (-686.44 m2/s2)/ (-19.6 m/s2) d = 35.0 m The solution above reveals that the vase will travel upwards for a displacement of 35.0 meters before reaching its peak. (Note that this value is rounded to the third digit.) The last step of the problem-solving strategy involves checking the answer to assure that it is both reasonable and accurate. The value seems reasonable enough. The vase is thrown with a speed of approximately 50 mi/hr (merely approximate 1 m/s to be equivalent to 2 mi/hr). Such a throw will never make it further than one football field in height (approximately 100 m), yet will surely make it past the 10-yard line (approximately 10 meters). The calculated answer certainly falls within this range of reasonability. Checking for accuracy involves substituting the calculated value back into the equation for displacement and insuring that the left side of the equation is equal to the right side of the equation. Indeed, it is! Kinematic equations provide a useful means of determining the value of an unknown motion parameter if three motion parameters are known. In the case of a free-fall motion, the acceleration is often known. And in many cases, another motion parameter can be inferred through a solid knowledge of some basic kinematic principles.RPMS Quiz: Quality vs. Efficiency 1. A teacher spends five hours creating a highly interactive digital game for a single 40-minute lesson. This is an example of prioritizing: • A) Quality over Efficiency • B) Efficiency over Quality • C) Administrative Competence • D) Resource Management • Hint: The focus is on high-level engagement, but the time investment is very high. 2. Which of the following best describes "Efficiency" in the context of the RPMS? • A) Submitting all MOVs and reports on or before the deadline with minimal errors. • B) Ensuring 100% of students pass the quarterly examination. • C) Creating the most aesthetically pleasing portfolio in the department. • D) Conducting home visits for every single student in a class of 50. • Hint: Look for the option that emphasizes timeliness and resource use. 3. Using a "template" or a "reusable slide deck" for lesson planning is a strategy to improve: • A) Efficiency • B) Instructional Diversity • C) Subject Matter Mastery • D) Classroom Discipline • Hint: Templates reduce the time spent on repetitive formatting. 4. If a teacher provides detailed, personalized feedback to every student but submits the grades two weeks late, they have achieved: • A) High Quality, Low Efficiency • B) Low Quality, High Efficiency • C) High Quality, High Efficiency • D) Low Quality, Low Efficiency • Hint: The work itself is excellent, but the timing is poor. 5. Which tool improves Efficiency without sacrificing the Quality of assessment data? • A) Automated Google Forms for multiple-choice quizzes. • B) Giving everyone a passing grade to save time on checking. • C) Writing long paragraphs of feedback on 200 paper-based essays. • D) Skipping assessments entirely to finish the syllabus faster. • Hint: Look for a balance where technology handles the "busy work." 6. When discussing Quality in your RPMS portfolio, which "Means of Verification" (MOV) is most appropriate? • A) Sample of student work with constructive teacher comments. • B) A logbook showing you arrived at school at 7:00 AM daily. • C) A certificate for attending a 1-hour webinar. • D) A photo of your organized teacher's cabinet. • Hint: Quality is evidenced by the impact on student learning. 7. The concept of "Doing the right things" (Effectiveness) represents: • A) Quality • B) Efficiency • C) Speed • D) Compliance • Hint: "Doing the right things" is about results; "Doing things right" is about process. 8. How does "Efficiency" help a teacher maintain "Quality" in the long run? • A) It prevents burnout by optimizing workload, leaving energy for creative teaching. • B) It allows the teacher to take more side jobs. • C) It ensures the teacher never has to talk to parents. • D) It proves that the teacher is smarter than their peers. • Hint: Consider the relationship between teacher well-being and performance. 9. If a teacher's RPMS rating for Quality is 5 (Outstanding) but Efficiency is 2 (Fair), what is the most likely reason? • A) The teacher produces excellent work but often misses deadlines. • B) The teacher is very fast but makes many mistakes in their reports. • C) The teacher is both slow and produces poor results. • D) The students are failing despite the teacher being very organized. • Hint: Check the gap between the high-standard output and the slow delivery. 10. What is the ultimate goal of balancing Quality and Efficiency in the PPST-RPMS? • A) To achieve sustainable professional excellence that benefits the learners. • B) To get a higher salary increase only. • C) To impress the School Head during the observation. • D) To finish the school year with the least amount of work possible. • Hint: It's about long-term growth for both teacher and student. ________________________________________ Answer Key: 1. A | 2. A | 3. A | 4. A | 5. A | 6. A | 7. A | 8. A | 9. A | 10. A ________________________________________Verb estar, thw plural og nouns and article in spanish, thing ion the classroom like desk, table, notebook, etc THINGS IN THE KITCHEN