A scientist labels the carbon atoms in a glucose molecule with a radioactive isotope. If the cell undergoes aerobic respiration, which of the following best describes the path and final destination of these labeled carbon atoms?

The carbons are released as CO_{2} during the oxidation of pyruvate and the Krebs cycle.

The carbons are converted into O _{2} gas and released through the plasma membrane.

The carbons are incorporated into H_{2}O molecules during the Electron Transport Chain.

The carbons are used to synthesize the ribose sugar found in ATP molecules.

During the transition step between glycolysis and the Krebs cycle, a single 3 -carbon pyruvate molecule is converted into a 2 -carbon acetyl-CoA molecule. What is the fate of the carbon atom that is lost during this process?

It is released as a molecule of CO_{2} in a decarboxylation reaction.

It remains in the mitochondrial matrix to be reused in the Calvin cycle.

It is reduced to form a molecule of methane ( CH_{4} ).

It binds with oxaloacetate to form a 5 -carbon intermediate.

In the carboxyl carbon of the resulting lactate molecules.

In the methyl group of the resulting lactate molecules.

In the CO_{2} gas released during the process.

In the central carbon atom of the resulting lactate molecules.

These carbons will be the last of the glucose carbons to be released as CO_{2} in the Citric Acid Cycle.

These carbons will be lost immediately during the cleavage of fructose-1,6-bisphosphate in glycolysis.

These carbons will never be released as CO_{2} and will instead be incorporated into cellular biomass.

These carbons will be released as CO_{2} during the conversion of pyruvate to acetyl-CoA.

Six molecules of carbon dioxide

The oxidation of pyruvate to acetyl-CoA

The conversion of citrate to isocitrate in the Krebs cycle

The formation of oxaloacetate from malate

The cleavage of fructose-1,6-bisphosphate in glycolysis

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