
Write the equation of the perpendicular bisector. :)
Quiz by M Cruz-Farooqi
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10 questions
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- Q1Write the equation of the perpendicular bisector that goes through the line segment with end points of ( 9, 5 ) and B ( -7 , 13 ).x - y = 1y = -x + 1y = x + 1x + y = 130s
- Q2What is the equation of the perpendicular bisector that goes through the line segment with end points of (10, -10) and B (2, 2)?y = 4x - 38y = 2x + 18y = -4x + 38y = -2x - 1830s
- Q3Write the equation of the perpendicular bisector that goes through the line segment with end points of (-10, -8) and B (-14, 8).y=-x+5y=x-5y=-2x+3y=2x-330s
- Q4Write an equation of the line in y = mx + b form that is the perpendicular bisector of the line segment having endpoints of (1,2) and (2,4).y = 4x + 2y = -2x + 5y = -2x + 3y = 2x + 130s
- Q5Write an equation of the line that is the perpendicular bisector of the line segment having endpoints of (-3,3) and (1,13).y = -x + 3y = x + 3y = -2x + 3y = 2x + 330s
- Q6Write an equation of the line that is the perpendicular bisector of the line segment having endpoints of (-4,4) and (0,-6).y = -x - 1y = x - 1y = 2x - 1y = -x + 130s
- Q7Write an equation of the line that is the perpendicular bisector of the line segment having endpoints of (-4,-2) and (8,4).y = -x + 1y = x + 5y = -0.5xy = 0.5x + 630s
- Q8Find the equation of the perpendicular bisector of AB for : A(3, - 3) and B(1, - 1).y = 2x - 1y = -2x + 1y = 1/2x + 1y = 1/2x - 130s
- Q9Find the equation of the perpendicular bisector of AB for A(1, 3) and B(- 3, 5).y = -x + 4y = 2x + 1y = x + 4y = -2x + 730s
- Q10Find the equation of the perpendicular bisector of AB for: A(3, 1) and B(-3, 6).y = -x + \frac{3}{2}y = 2x + \frac{7}{2}y = -x + \frac{7}{2}y = -2x + \frac{7}{2}30s