What does Ethics mean?

The knowledge of right and wrong. Guides to moral behavior.

North Carolina General Statute that states that Identification badges must be worn.

Activities of daily living, hygiene needs, positioning and providing exercise, nutrition, elimination of waste.

Any person having reasonable cause to believe that a disabled adult is in need of protective services shall report such information to the director.

Vulnerable Adults is what?

Adults who are at risk for abuse or mistreatment because they are not able to protect selves from harm due to mental, emotional, development disability; or brain damage; or changes from aging.

Failure to provide goods and services necessary to avoid physical harm, mental anguish, or mental illness

he NCBON refers to what a RN can legally do as “practice.”

Anyone who makes a report pursuant to this statute, who testifies in any judicial proceeding arising from the report, or who participates in a required evaluation shall be immune from any civil or criminal liability on account of such report or testimony or participation, unless such person acted in bad faith or with a malicious.

Invasion of Privacy is what?

Failure to prevent the intrusion of one person onto another. Violation of right to control personal information or the right to be left alone.

False statement made to a third person that causes a person shame or ridicule, or ruins their reputation; written is called libel; verbal is called slander

Unlawful restraining or restricting a person’s environment

An intentional deception or misrepresentation made by a person with knowledge that deception could result in some unauthorized benefit to self or some other person

Criminal Law is what?

Offenses against the public and society. May go to jail for breaking

False statement made to a third person that causes a person shame or ridicule, or ruins their reputation;

Rules made by government to help protect public. tell people what they can and cannot do.

intentional deception or misrepresentation made by a person with knowledge that deception could result in some unauthorized benefit to self or some other person

RN Practice is what ?

The NCBON refers to what a RN can legally do as “practice.”

Tasks that nurse aides are trained to do and legally able to do. The NCBON lists the tasks that NA Is can legally do.

Activities of daily living, hygiene needs, positioning and providing exercise, nutrition, elimination of waste.

Tasks that nurse aides are trained to do and legally able to do. The NCBON lists the tasks that NA Is can legally do.

Priorities for Resident Care is what

Activities of daily living, hygiene needs, positioning and providing exercise, nutrition, elimination of waste.

the NCBON refers to what a RN can legally do as “practice.”

Tasks that nurse aides are trained to do and legally able to do. The NCBON lists the tasks that NA Is can legally do.

The act of authorizing a person to act as a representative of another. The RN delegates to the nurse aide personal care tasks.

Failure to provide goods and services necessary to avoid physical harm, mental anguish, or mental illness

Giving care for which you are not allowed legally to perform

Assault is act of threatening to touch, or attempting to touch a person, without proper consent. Battery is touching a person without cons

1.02 Key Terms | Quizalize

DA 102 Microbiology Key Terms

In this video we take a look at the 0:02 fetch to code 0:03 execute cycle including its effect on 0:06 the various registers we've previously 0:12 [Music] 0:14 discussed a computer is defined Definition 0:17 as an electronic device that takes an 0:20 input 0:22 processes data 0:25 and delivers output 0:29 in this simple example you can see we're 0:31 taking the input 5 0:35 we're multiplying it by 2 that's our 0:37 process 0:39 and we're outputting 10. 0:44 but this could be way more complex for 0:46 example of a game console 0:48 the input could be the buttons you press 0:50 on a controller 0:53 the processes would then be carried out 0:55 by the console itself 0:59 and the output would be some form of 1:01 update to a monitor 1:02 and sound out for a speaker possibly 1:04 vibration feedback through the 1:06 controller 1:10 to process data a computer follows a set 1:13 of instructions 1:14 known as a computer program 1:18 if we take the lid off a typical desktop 1:20 computer we can identify 1:22 two critical components the memory 1:26 that stores the program and the central 1:29 processing unit or processor 1:31 which is under this large fan and 1:33 carries out the instructions 1:37 a computer carries out its function by 1:40 fetching 1:41 instructions decoding them and then 1:43 executing them 1:44 in a continuous repetitive cycle 1:46 billions of times a second 1:48 let's look at each of these stages in a 1:50 little more detail Fetch 1:53 so let's start with the fetch stage the 1:55 very first thing that happens 1:57 is the program counter is checked as it 2:00 holds the address 2:01 of the next instruction to be executed 2:07 the address stored is then copied into 2:09 the memory address register 2:14 the address is then sent along the 2:16 address bus to main memory 2:18 where it waits to receive a signal from 2:21 the control 2:22 bus so it knows what to do 2:27 as we want to read the data that's 2:29 stored in memory address 2:30 0 0 0 0 the control unit sends 2:34 a read signal along the control bus to 2:36 main memory 2:41 now main memory knows the data needs to 2:44 be read 2:45 the content stored in memory address 000 2:49 can be sent along the data bus to the 2:51 memory data register 2:56 now as we're currently in the process of 2:58 fetching an instruction 3:00 the data received by the memory data 3:03 register gets copied 3:04 into the current instruction register 3:11 the instruction effectively has now been 3:14 fetched from memory 3:16 just before we proceed to the decode 3:18 phase we now 3:19 increment the program counter so that 3:22 the address it contains 3:24 points to the address of the next 3:26 instruction which will need to be 3:30 executed 3:32 the instruction now being held in the 3:33 current instruction register 3:35 is ready to be decoded 3:39 now as we mentioned in the previous 3:41 video the instruction is made up of two 3:43 parts 3:44 we have the op code that's what it is we 3:47 need to do 3:50 and we have the operand what are we 3:53 going to do it to 3:55 now the operand could contain the actual 3:57 data 3:58 or indeed it could contain an address of 4:01 where the data is to be found 4:06 by decoding this instruction we can see 4:08 the operation we need 4:10 is a load operation so we need to load 4:14 the contents of memory location0101 4:18 into the cpus accumulator 4:25 in the exam a simple model will be used 4:27 to describe the 4:29 structure of any given instruction 4:32 you're not going to be expected to 4:34 define how an opcode is made up 4:36 but simply to interpret opcodes in the 4:39 given context of an exam 4:40 question in the example here 4:44 you can see there's a total of 16 4:46 different opcodes available 4:48 and this is because we're using four 4:50 bits for our representation 4:56 so now we've fetched the instruction and 4:59 we've decoded it so we know what we need 5:00 to do 5:01 we're finally ready to execute it 5:05 so we now send address 0101 5:08 to the memory dress register 5:13 now we're in the memory address register 5:15 we can finally send the address 5:18 down the address bus to main memory 5:24 this time we want to read the data 5:26 that's stored in memory 5:28 and so the control unit again sends a 5:30 read signal along the control bus 5:36 so main memories now receive an address 5:38 and a read signal 5:40 so the content stored at memory location 5:43 0101 5:44 can now be sent along the data bus back 5:46 to the cpu 5:47 and into the memory data register 5:54 finally the contents of the memory data 5:56 register are copied to the accumulator 5:59 and this is one of a number of general 6:00 purpose registers found in the cpu 6:04 this first instruction is now complete Branching 6:11 so what does this program actually do 6:14 you should be able to work it through 6:16 carefully and figure it out 6:19 we're now pointing instructions zero 6:21 zero zero one in the program counter 6:23 and we're ready to fetch the second 6:25 instruction 6:27 at the end of this video we're gonna 6:29 provide you with the answer 6:34 so let's talk a second about programs 6:37 that branch 6:40 on the left here we have a very simple 6:42 piece of pseudo code 6:44 line zero says first execute this line 6:46 of code 6:47 line 1 now execute this line and then 6:50 line 2 says 6:52 if the age is greater than 18 then 6:56 we're going to execute lines 3 and 4 6:58 otherwise 6:59 we're going to execute lines six and 7:02 seven 7:03 so this program doesn't necessarily 7:05 follow strictly in sequence from line 7:07 zero through to seven there's a chance 7:10 here the program may branch and jump 7:14 around 7:16 so we're going to pretend that this 7:17 program has been loaded into memory 7:20 each line of code on the left here has 7:23 ended up 7:24 as a location in memory now this is not 7:27 strictly how this would happen in this 7:28 one-to-one way 7:29 but for the purpose of example it's 7:31 absolutely fine 7:35 so the program counter starts by 7:37 pointing to memory address zero 7:39 and we fetch the first instruction 7:41 decode it and execute it 7:44 it then updates and tells us the next 7:47 instruction 7:48 is zero zero zero one because remember 7:50 the program counter is being incremented 7:52 so we fetch it decode it and we execute 7:55 line one of our program 7:59 we then fetch line two which in binary 8:01 is one 8:02 zero 8:06 now at this point depending on what 8:10 happens during the execution 8:11 of line two the program may be required 8:15 to fetch line three from memory or 8:18 line five from memory 8:25 so let's look at how this actually works 8:27 because we've said the program counter 8:28 simply gets incremented 8:31 well in the current instruction register 8:33 we have an instruction with the op code 8:36 0 1 1 0. 8:41 now when we look this up in the decode 8:43 unit we discover that this 8:45 code means branch always 8:51 this replaces the value held in the 8:54 program counter 8:56 with the contents of the operand that's 8:58 the second part of the instruction 9:01 from the current instruction register so 9:03 this case 9:04 one zero zero one 9:09 now when the next fetch cycle begins the 9:12 program counter is obviously checked 9:14 and as its contents have been previously 9:16 updated to a new memory location 9:19 and not simply incremented the program 9:22 effectively is able to jump 9:24 around memory 9:28 so having watched this video you should 9:30 be able to answer the following key 9:32 question 9:33 how does a cpu work 9:39 okay so let's um answer the question we 9:41 posed 9:42 earlier what did that program actually 9:48 do 9:50 so this is the first fetch to code 9:53 execute cycle 9:55 and this is the one that we ran through 9:57 in detail earlier 9:58 it effectively loaded the contents of 10:01 the memory 10:02 stored at location location0101 10:05 into the accumulator in other words 10:08 the dna number 3 is moved 10:11 from memory into the cpu 10:18 we then proceed onto the second fetch 10:20 decode execute cycle 10:23 now this one adds the contents of memory 10:27 located at 0 1 1 0 10:30 to the current contents of the 10:32 accumulator 10:34 so in other words the dna number one 10:38 because that's what's stored at address 10:40 zero one one zero 10:43 is added to the number three that was in 10:45 the accumulator 10:46 the results are stored back over the 10:48 accumulator 10:49 so effectively we've done three plus one 10:53 equals four 10:58 the third fetch to code execute cycle 11:00 stores the contents which are in the 11:02 accumulator 11:03 into memory location zero one one one 11:07 and that's because the op code the first 11:09 part of this current instruction 11:10 zero zero one one is the command to 11:13 store when we look it up in the decoder 11:15 unit 11:16 so in other words the result of the 11:17 previous calculation three plus one 11:19 equals four 11:20 is now written back into main memory 11:28 the fourth fetch decode execute cycle 11:30 outputs the contents of the accumulator 11:33 remember they were copied into main 11:34 memory but they're still held in the 11:35 accumulator 11:37 so in this simple abstraction the number 11:40 four is now 11:41 output to the user so they can see the 11:43 result of the calculation 11:49 the fifth and final fetch code execute 11:51 cycle 11:52 brings a halt to the current program 11:58 so this very simple program which has 12:01 five 12:02 fetch decode execute cycles has 12:04 performed the calculation 12:06 three plus one is then stored the result 12:09 in main memory 12:10 and displayed the result four to the 12:12 user 12:13 and in a high-level language this may 12:15 look something very similar to the 12:17 following two lines of code 12:20 sum variable equals num1 plus num2 12:24 print sum to the user 12:27 so you can start to get an appreciation 12:29 here of how the high level code you 12:32 write actually ends up being fetched 12:34 decoded 12:35 and executed inside a processor 12:38 of course your processor is doing 12:40 billions and billions of these 12:42 operations a second 12:43 which when you think about it is really 12:45 very impressive 12:52 [Music] 13:03 you. make 10 questions for a standerd of a level

Here is a quiz based on the “Reciprocal of a Linear Function” content from your PowerPoint. --- Quiz: Reciprocal of a Linear Function Multiple Choice (5 questions) Select the best answer. 1. What is the vertical asymptote of f(x) = \dfrac{1}{x - 3}? a) x = 0 b) x = 3 c) x = -3 d) y = 0 2. For f(x) = \dfrac{1}{2x + 4}, what is the y-intercept? a) 0 b) \dfrac{1}{2} c) \dfrac{1}{4} d) 2 3. What is the horizontal asymptote of any function of the form f(x) = \dfrac{1}{ax + b} (with a \neq 0)? a) y = 0 b) y = 1 c) x = 0 d) x = -\dfrac{b}{a} 4. The domain of f(x) = \dfrac{1}{5 - x} is a) all real numbers except 5 b) all real numbers except -5 c) all real numbers d) all real numbers except 0 5. As x approaches the vertical asymptote from the right, the values of f(x) a) approach 0 b) approach \pm\infty c) approach 1 d) approach the same value as from the left --- Completion (5 questions) Fill in the blank with the correct word or expression. 1. The vertical asymptote of a reciprocal linear function occurs where the ____________________ is zero. 2. The horizontal asymptote of f(x) = \dfrac{1}{ax + b} is the line y = ________. 3. A function of the form f(x) = \dfrac{1}{ax + b} has ______ x-intercept(s) because the numerator is constant. 4. The end behavior of f(x) = \dfrac{1}{x - 2} as x \to \infty is f(x) \to ________. 5. The y-intercept of f(x) = \dfrac{1}{3x - 6} is ________. --- Answer Key Multiple Choice 1. b) x = 3 2. c) \dfrac{1}{4} (Substitute x = 0: f(0) = \frac{1}{4}) 3. a) y = 0 4. a) all real numbers except 5 5. b) approach \pm\infty Completion 6. denominator 7. 0 8. no / zero 9. 0 (from the positive side) 10. -\dfrac{1}{6} (Substitute x = 0: f(0) = \frac{1}{-6})

KEY LINKS UNIT 10 (81-102)

1.02-1.03 Skeletal System

1.02 Vocab

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